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Aleonysh [2.5K]
3 years ago
5

A car is travelling around a circular track at a steady speed. A force causes it to follow the track.

Physics
1 answer:
Fittoniya [83]3 years ago
4 0

The force that keeps the car moving in a circle is perpendicular to the car's velocity. The force points toward the center of the circle. The angle is <em>90°</em>.

The diagram that illustrates my answer is attached hereunto.

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Davisson and Germer performed their experiment with a nickel target for several electron bombarding energies. At what angles wou
pochemuha

Answer:

The angle of diffraction are 67.75 deg and 53.57 deg.

Explanation:

Given:

Davisson and Germer  experiment with nickel target for electrons bombarding.

Voltages : 38\ eV and 54\ eV

We have to find the angles that is  \phi_3_8 and \phi_5_4 .

Concept:

  • Davison Germer experiment is based on de Broglie hypothesis where it says matter has both wave and particle nature.
  • When electrons get reflected from the surface of a metal target with an atomic spacing of D, they form diffraction patterns.
  • The positions of diffraction maxima are given by Dsin(\phi) = n\lambda .
  • An atomic spacing is D = 0.215\ nm, when  the principal maximum corresponds to n=1
  • The wavelength is \lambda, and   \lambda =\frac{1.227 \sqrt{V} } {\sqrt{V_o}}\ nm .

Solution:

Finding the wavelength at V_o=38\ eV .

⇒ \lambda_3_8 =\frac{1.227 \sqrt{V} } {\sqrt{38V}}\ nm

⇒ \lambda_3_8 =0.199 nm

    Plugging the values of wavelength.

⇒  sin(\phi)=\frac{\lambda}{D}

⇒  \phi_3_8=sin^-1(\frac{0.199}{0.215} )

⇒ \phi_3_8 =67.75 degrees.

Now

For for the electrons with energy 54\ eV, V_0=54V the wavelength is.

⇒ \lambda_5_4 =\frac{1.227 \sqrt{V} } {\sqrt{54V}} = 0.173 nm

And

⇒ \phi_5_4=sin^-1(\frac{0.173}{0.215} ) = 53.57 degrees.

So,

The angles of diffraction maxima are 67.75 deg and 53.57 deg.

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