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skad [1K]
2 years ago
6

Solve the following equation for X, if Y = 3 and Z = -1. 3XY- 5XZ^2+Y=19

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
5 0
Y=7-4*[4-3^3]-7888=421
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gavin bought 2 1/2 cubic yards of topsoil for $75 what is the unit rate in cost per cubic yard for the topsoil
Kruka [31]

Answer:

$30

Step-by-step explanation:

Divide the cost ($75) by the yards (2 1/2) to get $30 per yard.

7 0
3 years ago
Read 2 more answers
Write as many equivalent expressions to 3/4(4x-8)+1/4(4x-8)
Deffense [45]

Answer:

4x-8

Step-by-step explanation:

3/4(4x-8)+1/4(4x-8)

12/4x-24/4+4/4x-8/4

3x-6+x-2

3x+x-6-2

4x-8

8 0
3 years ago
Read 2 more answers
Help me please thanks.
kap26 [50]

Answer:

Step-by-step explanation:

4 0
3 years ago
A rectangular board has an area of 648 square centimeters. The triangular part of the board has an area of 162 square centimeter
maksim [4K]

Answer:

25%.

Step-by-step explanation:

Let E be the event that the dart lands inside the triangle.

We have been given that a rectangular board has an area of 648 square centimeters. The triangular part of the board has an area of 162 square centimeters.

We know that probability of an event represents the chance that an event will happen.

\text{Probability}=\frac{\text{Favorable no. of events}}{\text{Total number of possible outcomes}}

\text{Probability that dart lands inside the triangle}=\frac{\text{Area of triangle}}{\text{Area of rectangle}}

\text{Probability that dart lands inside the triangle}=\frac{162}{648}

\text{Probability that dart lands inside the triangle}=0.25

Convert into percentage:

0.25\times 100\%=25\%

Therefore, the probability that dart lands inside the triangle is 25%.

7 0
3 years ago
Read 2 more answers
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
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