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1 year ago

How many lines of symmetry does the following figure have ?

Mathematics

1 answer:

KIM [24]1 year ago

8 0

Answer:

Step-by-step explanation:

It has only 1 line of symmetry. The line is a vertical line that passes through the top vertex.

Answer: 1

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The buyer for a chain of stores purchased lawn ornaments in bulk, paying $23 each. The stores will sell each lawn ornament for $

Naya [18.7K]

Answer:

The markup percentage is 61.2

Step-by-step explanation:

Given as :

The cost price of each ornaments = $23

The sell price of each ornament = $37.08

Let The markup percentage = x

<u>Now, According to question</u>

Markup percentage = $\dfrac{s.p - c.p}{c.p}$ × 100

Or, x% = $\dfrac{37.08 - 23}{23}$

Or, x% = $\dfrac{14.08}{23}$

Or, x% = 0.612

∴ x = 0.612 × 100

I.e x = 61.2

So, The The markup percentage = x = 61.2

Hence, The markup percentage is 61.2 Answer

8 0

3 years ago

What is 4(x 2) = 48 simplified?

Nookie1986 [14]

4(x 2)=48
4x+8=48
4x=40
x=10

6 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

Apr 23, 8:46:54 AM<br> What is the missing term?

kipiarov [429]

Answer: -10x
Explanation: Multiply -2 by 5x

7 0

2 years ago

in 1930 the average cost for a gallon of gasoline was $0.25. in 2007 the average cost for a gallon of gasoline is $2.60 what is

AlekseyPX

Hello! The first thing to do is to find the amount of change by subtracting both numbers. 2.60 - 0.25 is 2.35. Now, we set up a proportion by doing change/original = x/100. With the values plugged in, it would be written like this: 2.35/0.25 = x/100. Cross multiply the values in the proportion. When you do, you get 235 = 0.25x. Now, divide each side by 0.25 to isolate the "x". When you do that, x = 940. The price of gas has gone up 940% since 1930.

7 0

2 years ago

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