Flame of fire could get put out with water
Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;

Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.
Convert km to m. -> 320km=320000 m
Convert hours to seconds -> 4 hrs=14400 s
Divide the distance by time because v=d/t
320000/14400=22.22 m/s
Explanation:
It is given that,
Height of the building, h = 44 m
Initial horizontal velocity,
Initial vertical velocity,
It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.
The formula for the maximum height is given by :

g is the acceleration due to gravity

The total maximum height, h' = h + H

The formula for the time of flight is given by :


Hence, this is the required solution.