1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tamaranim1 [39]
2 years ago
10

What is the term for producing a current by moving a wire through a magnetic field?.

Physics
1 answer:
maria [59]2 years ago
6 0
The answer is electromagnetic Induction.



I hope this answer will help you
You might be interested in
Two blocks of masses 8 kg and 4.3 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them
oee [108]

Answer:

The velocity of other mass is 3.60 m/s.

Explanation:

Given that,

Mass of first block = 8 kg

mass of second block = 4.3 kg

Speed = 6.7 m/s

We need to calculate the speed of first mass

Using conservation of momentum

(m_{1}+m_{2})u=m_{1}v_{1}+m_{2}v_{2}

where, m₁ =mass of first block

m₂ =mass of second block

m₁ =mass of first block

v₂ =speed of second block

Put the value into the formula

8+4.3\times0=8\times v_{1}+4.3\times6.7

v_{1}=\dfrac{-4.3\times6.7}{8}

v_{1}=-3.60\ m/s

Negative sign represent the opposite direction of initial value.

Hence, The velocity of other mass is 3.60 m/s.

3 0
3 years ago
An electron in the beam of a TV picture tube is accelerated through a potential difference of 2.00 kv.?It then passes into a mag
Stells [14]

Answer:

The magnitude of the field is 8.384×10^-4 T.

Explanation:

Now, i start solving this question:

First, convert the potential difference(V) 2 kv to 2000 v.

As, we have the final formula is qvB = mv^2/r. It came from the centripetal force and the magnetic force and we know that these two forces are equal. When dealing with centripetal motion use the radius and not the diameter so

r = 0.36/2 = 0.18 m.

As, we are dealing with an electron so we know its mass is 9.11*10^-31 kg and its charge (q) is 1.6*10^-18 C.

We can solve for its electric potential energy by using ΔU = qV and we know potential energy initial is equal to kinetic energy final so ΔU = ΔKE and kinetic energy is equal to 1/2mv^2 J.

qV = 1/2mv^2

(1.6*10^-19C)(2000V) = (1/2)(9.11*10^-31kg) v^2

v = 2.65×10^7 m/s.

These all above steps we have done only for velocity(v) because in the final formula we have 'v' in it. So, now we substitute the all values in that formula and will find out the magnitude of the field:

qvB = mv^2/r

qB = mv/r

B = mv/qr

B = (9.11*10^-31 kg)(2.65×10^7 m/s) / (1.6*10^-19 C)(0.18 m)

Hence, B = 8.384*10^-4 T.

5 0
3 years ago
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

E=\dfrac{Q}{4\pi\epsilon_0 r^2}

Substitute numerical values:

E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0
2 years ago
Which layer of the atmosphere has the lowest density?
stich3 [128]
Hello,

The exosphere is the lowest<span> in density of the </span>layers of the atmosphere.

The higher up you get into the atmosphere, the lower the density becomes. Thus, the troposphere has the highest density of the five layers. 

Faith xoxo
6 0
3 years ago
What is the best way to dress for an outdoor trip in cold weather?
kolezko [41]

Answer: A: wear several thin layers and a waterproof top layer

Explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • The magnetic dipole moment of Earth is 8.00 ✕ 1022 J/T. Assume that this is produced by charges flowing in Earth's molten outer
    5·1 answer
  • The diameter of a lead pipe was measured to be 2.40 centimeters. its diameter in units of meters is ________.
    13·1 answer
  • an 80 kg cart goes around the inside of a vertical loop of a roller coaster. the radius of the loop is 5m and the cart moves at
    12·1 answer
  • State the principle of work-kinetic energy theorem.
    14·2 answers
  • If the mass of an object halves, how does that affect its kinetic energy
    5·1 answer
  • What is the difference between negative and positive acceleration?
    10·1 answer
  • 1. A step-up transformer increases 15.7V to 110V. What is the current in the secondary as compared to the primary? Assume 100 pe
    9·1 answer
  • 1. On each of your equipotential maps, draw some electric field lines with arrow heads indicating the direction of the field. (H
    13·1 answer
  • 1. How can researchers, educators, and policymakers encourage journalists and others to discuss
    13·1 answer
  • A toroid with a square cross section 3.0 cm × 3.0
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!