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Scorpion4ik [409]
3 years ago
12

As a 5.0 × 10^2-newton basketball player jumps

Physics
1 answer:
AysviL [449]3 years ago
4 0
     This player is initially at rest, then the Force Weight (W) and the Normal Force (N) have a same module. When applies a Extra Force (E) on the floor, this reacts with this increase, causing the player to be released upwards.
     Using the Newton's Secound Law, we have:

F_{R}=ma \\ W+E-N=ma \\ N =W+E \\ N=5*10^2+10*10^2 \\ \boxed {N=1.5*10^3N}

Number 3

If you notice any mistake in my english, please let me know, because i am not native.
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S_A_V [24]

The answer is:

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The explanation:

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A positive test charge q is released from rest at distance r away from a charge of Q and a distance 2r away from a charge of 2Q.
Luba_88 [7]

Answer: Option (b) is the correct answer.

Explanation:

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Therefore, the net force will be as follows.

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7 0
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Convert 2 kg to cg give you answer in SI
BARSIC [14]

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2 years ago
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Use this formula to find your answer...

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frequency (f)=1/( Time period).

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