9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent

Skater begins to spend with arms held out at shoulder height. The skater wants to match the speed of the spin to the beat of the

Aleksandr [31]

Answer:

the moment of inertia with the arms extended is Io and when the arms are lowered the moment

I₀/I > 1 ⇒ w > w₀

Explanation:

The angular momentum is conserved if the external torques in the system are zero, this is achieved because the friction with the ice is very small,

L₀ = L_f

I₀ w₀ = I w

w = $\frac{I_o}{I}$ w₀

where we see that the angular velocity changes according to the relation of the angular moments, if we approximate the body as a cylinder with two point charges, weight of the arms

I₀ = I_cylinder + 2 m r²

where r is the distance from the center of mass of the arms to the axis of rotation, the moment of inertia of the cylinder does not change, therefore changing the distance of the arms changes the moment of inertia.

If we say that the moment of inertia with the arms extended is Io and when the arms are lowered the moment will be

I <I₀

I₀/I > 1 ⇒ w > w₀

therefore the angular velocity (rotations) must increase

in this way the skater can adjust his spin speed to the musician.

7 0

3 years ago

What Do You Get When You Multiply An Object's mass times the acceleration?

emmasim [6.3K]

You get the net force acting on it ... the sum of the strengths and directions
of all the individual forces there may be.

7 0

3 years ago

How would you find the total energy stored in the

likoan [24]

Answer:

The energy of the capacitors connected in parallel is 0.27 J

Given:

C = $2.0\micro F = 2.0\times 10^{- 6} F$

C' = $4.0\micro F = 4.0\times 10^{- 6} F$

Potential difference, V = 300 V

Solution:

Now, we know that the equivalent capacitance of the two parallel connected capacitors is given by:

$C_{eq} = C + C' = 2.0 + 4.0 = 6.0\micro F = 6.0\times 10^{- 6} F$

The energy of the capacitor, E is given by;

$E = \frac{1}{2}C_{eq}V^{2}$

$E = \frac{1}{2}\times 6.0\times 10^{- 6}\times 300^{2} = 0.27 J$

6 0

3 years ago

Which the answer It's science

earnstyle [38]

The answer is A. ive done a 5-k race, so its for sure 3 miles.

3 0

3 years ago

How does being on the moon effect gravitational field strength

SVETLANKA909090 [29]

Your being on the moon has no effect on the moon's
gravitational field strength, or on the Earth's for that
matter.

However, YOU notice a change on YOU when YOU move
from one to the other, because of the effect of the gravitational
field strength on you and your internal organs.

If you could stand on the moon, you would experience an incredible
sense of lightness, since the forces of attraction between the moon
and anything else are only 16% as great as the same forces are on
Earth.

5 0

4 years ago