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sergejj [24]
3 years ago
9

Tony ran 600 meters in 60 seconds. What was Tony's speed during the race?

Physics
2 answers:
Ray Of Light [21]3 years ago
7 0
Tony's speed during the race was 10
NARA [144]3 years ago
4 0
10 meters per second.
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The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational
zzz [600]

Answer:

P=3.61\times 10^{-3}\ Pa

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

P=\dfrac{F}{A}

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa

So, the maximum pressure created by brick is 3.61\times 10^{-3}\ Pa.

5 0
3 years ago
A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from
ladessa [460]

Answer:

P_1 = 1166.7 Watt

P_2 = 2000 Watt

Explanation:

Average power for the human sprinter is given as

Power = \frac{\Delta E}{\Delta t}

so we have

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(70)(10^2) - 0}{3}

P_1 = 1166.7 Watt

Average power for greyhound is given as

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(30)(20^2) - 0}{3}

P_2 = 2000 Watt

3 0
3 years ago
What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?
fiasKO [112]
Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.

v = momentum ÷ m
   = (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s

kinetic energy = (mv∧2)÷2
                       = (9.1×10∧-31 × 1,153,846.154∧2) ÷2
                      = (1.21154×10∧-18) ÷ 2
                      = 6.05769×10∧-19 J
4 0
3 years ago
Read 2 more answers
A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i
Lubov Fominskaja [6]

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

3 0
3 years ago
Fill in the blanks.<br>In what way are speed and velocity different?​
IrinaVladis [17]
Volocity can be the wave length of the speed like the volume.
8 0
3 years ago
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