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Musya8 [376]
3 years ago
9

What is the speed of a 48-kilogram dog running acrossa lawn with 216 joules of kinetic energy?​

Physics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

3m/s

Explanation:

K.E= (1/2)mv^2

216j= (1/2)48kg • v^2

216J=24kg•v^2

v^2 = (216J)/(24kg)

v^2= 9m^2/s^2

/sqrt{v^2} = /sqrt{9m^2/s^2}

V =3m/s

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Since the temperature remains constant, we have

P_{f} V_{f} = P_{i} V_{i}\\(101325) V_{f} = (151795) V_{i}\\V_{f} = 1.5 V_{i}

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