What is the speed of a 48-kilogram dog running acrossa lawn with 216 joules of kinetic energy?

Physics

1 answer:

pishuonlain [190]3 years ago

8 0

Answer:

3m/s

Explanation:

K.E= (1/2)mv^2

216j= (1/2)48kg • v^2

216J=24kg•v^2

v^2 = (216J)/(24kg)

v^2= 9m^2/s^2

/sqrt{v^2} = /sqrt{9m^2/s^2}

V =3m/s

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