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WINSTONCH [101]
3 years ago
15

Applying the Law of Conservation of Energy. If a car was released down the track from a height what happens to the potential ene

rgy and Kinetic energy as the car goes down the ramp?
Physics
1 answer:
erastova [34]3 years ago
4 0

Answer:

According to the law of conservation of energy, energy cannot be created or destroyed,  although it can be changed from one form to another.    KE + PE = constant. A simple example involves a stationary car at the top of a hill.  As the car coasts down the hill, it moves faster and so it’s kinetic energy increases and it’s potential energy decreases.  On the way back up the hill, the car converts kinetic energy to potential energy.  In the absence of friction, the car should end up at the same height as it started.

This law had to be combined with the law of conservation of mass when it was determined that mass can be inter-converted with energy.

One can also imagine the energy transformation in a pendulum.  When the ball is at the top of its swing, all of the pendulum’s energy is potential energy.   When the ball is at the bottom of its swing, all of the pendulum’s energy is kinetic energy.   The total energy of the ball stays the same but is continuously exchanged between kinetic and potential forms

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6. A .25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. a. What is the final
Alenkasestr [34]

Answer:

(a) the final velocity of the combined mass is 9.43 m/s

(b) the decrease in kinetic energy during the collision is 386.1 J

Explanation:

Given;

mass of arrow, m₁ = 25 kg

initial velocity of arrow, u₁ = 12 m/s

mass of target, m₂ = 6.8 kg

initial velocity of the target, u₂ = 0

Part (a)

From the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = v(m₁+m₂)

where;

v is the final velocity of the combined mass

25 x 12 + 0 = v(25 + 6.8)

300 = v(31.8)

v = 300/31.8

v = 9.43 m/s

Part(b)

Kinetic Energy, K.E = ¹/₂mv²

Initial kinetic energy =  ¹/₂m₁u₁² + ¹/₂m₂u₂²  = ¹/₂ x 25 x (12)² + 0 = 1800 J

Final kinetic energy = ¹/₂m₁v² + ¹/₂m₂v² = ¹/₂v²(m₁ + m₂)

                                                               = ¹/₂ x (9.43)²(25+6.8)

                                                               = 1413.91 J

Decrease in kinetic energy = Initial K.E - Final K.E

Decrease in kinetic energy = 1800J - 1413.91 J = 386.1 J

                               

4 0
3 years ago
What can iron filings sprinkled on a piece of paper demonstrate?
jolli1 [7]
<span>c the pattern of the magnetic fields lines</span>
6 0
3 years ago
What is the mass of a car that weighs 12kN?<br> Will give brainliest!!!!
masha68 [24]

Answer:

The answer is 1200 Kg

Explanation:

<h3><u>Given</u>;</h3>
  • Weight of car 12000 N
<h3><u>To </u><u>Find</u>;</h3>
  • Mass of car = ?
<h3><u>Formula</u>;</h3>
  • W = m × g
  • where, W = weight
  • m = mass,
  • g = Acceleration due to gravity = 10 m/s²

Now,

W = mg

12000 = m ÷ 10

m = 12000 ÷ 10

m = 1200 kg

Thus, The mass of car is 1200 kg or 1.2k Kg.

 

<u>-TheUnknownScientist 72</u>

7 0
2 years ago
The velocity-time graph of a body is given. What quantities are represented by (a) slope of the graph and (b) area under the gra
iogann1982 [59]

Answer:

a) acceleration

b) displacement

Explanation:

The velocity-time graph is a graph of velocity versus time. The velocity (m/s) would be on the Y-axis while time (s) would be on the X-axis.

a) The slope of a graph is given by: <em>change in Y-axis/change in X-axis</em> = ΔY/ΔX

In a velocity-time graph, ΔY = change in velocity and ΔX = change in time.

Hence, the slope of a velocity-time graph becomes: <em>change in velocity/change in time.</em>

Also, acceleration = change in velocity/change in time.

Hence, the slope of a velocity-time graph = acceleration.

b) Assuming that the area under a velocity-time graph is a rectangle, the area is given as:

Area of a rectangle = length x breadth

                                  = velocity x time (m/s x s)

Also, displacement = velocity x time (m)

Hence, <em>the area under a velocity-time graph of a body would give the displacement of the body</em>.

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3 years ago
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