<span>The total number (n) = 28. This includes the number of cats (c) and the number of dogs (d), which is three times the number of cats. Therefore n = c + d and 28 = c + 3c. 28 = 4c. C = 28/4. C = 7. Kim trained 7 cats.</span>
I'd use synthetic div. here, with 2 as my divisor:
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2 / 1 -11 18
2 -18
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1 -9 0
Note that the coefficients of the missing factor are given here and are 1 and -9. Thus, (x-9) is the missing factor.
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Lets go step by step and factor out each as we go
first lets factor out a 3 since 3 is common in 9 and 3
3(3ab^2 - abc)
now lets factor out a since its common in both
3a(3b^2 - bc)
now lets factor out a b since its common in both
3ab(b - c)
we can't factor anything else out so we are done.