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Elden [556K]
3 years ago
10

A circular saw blade with a radius of 0.145 m starts from rest and turns in a vertical plane with a constant angular acceleratio

n of 2.00 rev/s2. After the blade has turned through 155 revs, a small piece of the blade breaks loose from the top of the blade. After the piece breaks loose, it travels with a velocity that is initially horizontal and equal to the tangential velocity of the rim of the blade. The piece travels a vertical distance of 0.820 m to the floor.
How far does the piece travel horizontally, from where it broke off the blade until it strikes the floor?

Physics
1 answer:
Vikki [24]3 years ago
7 0

Answer:

Horizontal distance travelled will be x= 9.40 m

Explanation:

Detailed solution is attached

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