A circular saw blade with a radius of 0.145 m starts from rest and turns in a vertical plane with a constant angular acceleratio
n of 2.00 rev/s2. After the blade has turned through 155 revs, a small piece of the blade breaks loose from the top of the blade. After the piece breaks loose, it travels with a velocity that is initially horizontal and equal to the tangential velocity of the rim of the blade. The piece travels a vertical distance of 0.820 m to the floor.
How far does the piece travel horizontally, from where it broke off the blade until it strikes the floor?
How far does the piece travel horizontally, from where it broke off the blade until it strikes the floor?
1 answer:
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The momentum of the second object is 125 kg m/s
Explanation:
The momentum of an object is given by
where
m is the mass of the object
v is its velocity
For the object in this problem,
And its mass is m and its velocity is v.
The second object has a mass of and same velocity v, so its momentum is
So, the second object has a momentum that is half of the momentum of the first object, therefore it is:
Learn more about momentum:
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