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blondinia [14]
4 years ago
6

Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject

ory to Saturn. Calculate the time required for the mission. Assume the propulsion system has a specific impulse of 300 s.
Physics
1 answer:
Finger [1]4 years ago
6 0

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}

where

\mu_{sun} is gravitational parameter of sun =  1.32712 x 10^20 m^3 s^2.t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}

t = 12,105.96 sec

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A physicist comes across an open container which is filled with two liquids. Since the two liquids have different density, there
Dominik [7]

Answer:

496.57492 kg/m³

Explanation:

P_a = Atmospheric pressure = 101300 Pa

\rho_w = Density of water = 1000 kg/m^3

h_w = Height of water = 21.8 cm

h_f = Height of fluid = 30 cm

g = Acceleration due to gravity = 9.81 m/s²

\rho_f = Density of the unknown fluid

Absolute pressure at the bottom

P_{abs}=P_a+\rho_wgh_w+\rho_fgh_f\\\Rightarrow \rho_f=\frac{P_{abs}-P_a-\rho_wgh_w}{gh_f}\\\Rightarrow \rho_f=\frac{104900-101300-1000\times 9.81\times 0.218}{9.81\times 0.3}\\\Rightarrow \rho_f=496.57492\ kg/m^3

The density of the unknown fluid is 496.57492 kg/m³

6 0
3 years ago
NEED HELP PLEASE!!!!!! 19 POINTS!!
podryga [215]
When the kinetic energy is transformed into another for of energy during the collision or impact  
5 0
3 years ago
A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

2.7 s = \frac{18}{v}

v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

6.67 = \sqrt{\frac{T}{0.67}}

so we will have

T = 29.6 N

5 0
4 years ago
What is the flow of energy from the falling water to the steam?
kenny6666 [7]

Answer:

The flow of energy from falling water to the steam is;

a) Mechanical → Mechanical → Electrical → Thermal → Thermal

Explanation:

1) Mechanical → Mechanical

The water in the pipe before it falls possesses potential energy which it converts into kinetic energy as it falls from height

2) Mechanical → Mechanical

The water falling from the pipe stream unto the turbine wheel transfers its kinetic (mechanical) energy due to its motion on to the turbine wheel to give the wheel rotational motion

3) Mechanical → Electrical

The kinetic (mechanical) energy from the rotating turbine wheel is converted into electrical energy in the electrical generator which transported through the electrical circuit

4) Electrical → Thermal

The electrical energy from the electric current is then converted into thermal energy as the current passes through the resistors in the heating filament

5) Thermal → Thermal

The heated filament transfers thermal energy to the the water in the beaker by conduction which raises the temperature of the water such that as the water acquires more thermal energy it turns into steam

Therefore, we have the flow of energy from the falling water to steam as follows;

1) Mechanical 2) Mechanical 3) Electrical 4) Thermal 5) Thermal

3 0
3 years ago
A baseball player hits a 140 g baseball with a force of 2800 N. What is the
Murljashka [212]
B because 2800 divide by 40 is 20
6 0
3 years ago
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