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ki77a [65]
3 years ago
6

What is the deceleration of a bicycle that goes from 40m/s to 20m/s in 5 seconds

Physics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

-4 m/s^2

Explanation:

The acceleration of the bycicle is given by:

a=\frac{v-u}{t}

where

v = 20 m/s is the final velocity of the bike

u = 40 m/s is the initial velocity

t = 5 s is the time interval

Substituting numbers, we find

a=\frac{20 m/s-40 m/s}{5s}=-4 m/s^2

and the acceleration is negative, which means that the bycicle is slowing down.

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Alexxandr [17]

Answer:

7,79 seconds

Explanation:

{\displaystyle {\overline {a}}={\frac {\Delta v}{t}}}

You need to use the acceleration formula. A is acceliration, \displaystyle \Delta \mathbf {v} is change in velocity and t is time.

You  need to multiply the formula with t and divide by a and you get

a*t=\displaystyle \Delta \mathbf {v}

t= \displaystyle \Delta \mathbf {v}/a

after that you just need to insert the numbers

change in velocity is 76.4 minus 0.

acceliration is gravitational acceleration which is 9.81.

After that you get

t=76.4/9.81

t= 7,787971458 s

6 0
3 years ago
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answer -

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