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2 years ago

Which word describes Arette? A. Trilingual B. Bilingual C. Monolingual

Physics

1 answer:

timurjin [86]2 years ago

8 0

Arette is considered bilingual.

Within the context of this question, Arette is from France but speaks two different language

<h3>What is bilingual?</h3>

Bilingual is a word which is usually, frequently and most of the times used to describes a person, community or a nation that speaks two languages.

I myself too; I am bilingual; I speak English and Yoruba

Generally, people who speak more more more than one language are considered as linguists

In conclusion, Arette is considered bilingual.

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Nuclear decay occurs according to first-order kinetics. How long will it take for a sample of radon-218 to decay from 99 grams t

dedylja [7]

It will take 267 milliseconds for a sample of radon-218 to decay from 99 grams to 0. 50 grams.

We know that half life of a first order reaction is given by: $t_{1/2} = 0.693/k$

where k = rate of reaction

Given half life = 35 milliseconds

So from this we get k = 0.0198

Now we know that rate of first order reaction is given by: $kt= 2.303 * log(R'/R)$

where t= time

R'= initial amount = 99 g

R= final amount= 0.50 g

k= rate of reaction = 0.0198

Putting values of these in above equation we get t=267 milliseconds.

i.e. It will take 267 milliseconds for a sample of radon-218 to decay from 99 grams to 0. 50 grams.

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4 0

1 year ago

If a string vibrates at the fundamental frequency of 528 Hz and also produces an overtime with a frequency of 1,056 Hz this over

Romashka-Z-Leto [24]

I have a hunch that you're not talking about overtime
OR overtune. I think you're going for overtone .

For a fundamental frequency of 528 Hz,
1,056 Hz is the second harmonic.

5 0

3 years ago

The greater the surface area of a piece of fission material, the

oksian1 [2.3K]

The answer would be b

7 0

3 years ago

A 0.877-kg ball has an elastic, head-on collision with a second ball that is initially at rest. The second ball moves off with h

Art [367]

Answer: the mass of the second ball is 2.631 kg

Explanation:

Given that;

m1 = 0.877 kg

Initial velocity = V0

Initial momentum = m1 × V0

final velocity of m1 is u1, final velocity of m2 is u2 = v0/2

now final momentum = m1 × u1 + m2 × u2

using momentum conservation;

m1×V0 = m1×u1 + m2×v0/2

m1×(v0 - u1) = m2×V0/2 ----- let this be equation 1

Now, for elastic collision;

m1×v0²/2 = m1×u1²/2 + m2×(v0/2)²/2

m1×(v0² - u1²) = m2×(v0/2)² --------- let this be equation 2

now; equation 2 / equation 1

: V0 + u1 = v0/2

2V0 + 2u1 = V0

2u1 = V0 - 2V0

u1 = -V0/2

now we insert in equ 1

m1×3V0/2= m2×V0/2

m1 × 3 = m2

m2 = 0.877 × 3

m2 = 2.631 kg

Therefore, the mass of the second ball is 2.631 kg

7 0

3 years ago

Question 2 (1 point)

Leviafan [203]

The car takes 10.8 seconds to reach a velocity of 42.1 m/s

Explanation:

The motion of the car is at constant acceleration, so we can use the following suvat equation:

$v=u+at$

where

v is the final velocity of the car

u is its initial velocity

a is the acceleration

t is the time

For the car in this problem, we have:

u = 15.0 m/s

v = 42.1 m/s

$a=2.50 m/s^2$

Solving for t, we find the time it takes for the car to reach that velocity:

$t=\frac{v-u}{a}=\frac{42.1-15.0}{2.50}=10.8 s$

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3 0

2 years ago