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eduard
3 years ago
14

A link in a mechanism is to be subjected to a tensile force that varies from 3500 to 500 N in a cyclical fashion as the mechanis

m runs. It has been decided to use SAE 1040 cold-drawn steel. Complete the design of the link, specifying a suitable cross-sectional shape and dimensions.
Physics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

Design explained below

Explanation:

We are designing a link which is able to sustain 3500 N force because it will automatically sustain any lower force.

 

The tensile strength of AISI 1040 steel is : 585 MPa

Shear Strength = 338.15 MPa from data book

Now, 585 * 10^6 = 3500 / [Area]

(from pressure = force / area)

So, area = 5.98*10^-6= pi / 4 * d^2

So, diameter = 2.76 mm

Also, 338.15 *10^6 = 3500 / (pi * d * L)

So, L = 37.5 mm

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Answer:

3000 newton force is required

Explanation:

F = ma

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F=3000(kgs x m/s^2)

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3 years ago
A 0.12-kg metal rod carrying a current of current 4.1 A glides on two horizontal rails separation 6.3 m apart. If the coefficien
Neporo4naja [7]

Answer:

The magnetic field is B  =  8.20 *10^{-3} \  T

Explanation:

From the question we are told that

   The  mass of the metal rod is  m  = 0.12 \ kg

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    The distance of separation(equivalent to length of the rod ) is L   = 6.3 \ m

     The coefficient of kinetic friction is \mu_k  =  0.18

      The kinetic frictional force is  F_k  = 0.212 \ N

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Generally the magnetic force on the rod is mathematically represented as  

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For  the rod to move with a constant velocity the magnetic force must be equal to the kinetic frictional force so

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=>      B  =  \frac{F_k}{L  *  I  }

=>       B  =  \frac{0.212}{ 6.3   *  4.1   }

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Which of these devices does NOT contain a magnet or electromagnet?
Black_prince [1.1K]
I think it is D a light bulb
7 0
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Answer:

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radio waves  > 1 mm

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(c) No

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