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3 years ago

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In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that i

s a distance d from the point of release. If this distance was doubled, what would the new speed be, assuming air resistance is negligible?

1 answer:

NikAS [45]3 years ago

4 0

Answer:

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

Explanation:

As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here

$v_f^2 - v_i^2 = 2 a d$

since we released it from rest so we have

$v_i = 0$

so here we have

$v_f = \sqrt{2gd}$

now if the distance is double then we have

$v_f' = \sqrt{2g(2d)}$

now from above two equations we can say that

$v_f' = \sqrt2 v_f$

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

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