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Travka [436]
4 years ago
14

Garrick rubs an inflated balloon against his hair. He then touches the balloon against a non-conducting wall.

Physics
1 answer:
Sauron [17]4 years ago
7 0

Answer:

Figure A

Explanation:

At first, the inflated balloon is rubbed against the hair.

In this situation, the balloon is charged by friction: because of the friction between the surface of the balllon and the hair, electrons are transferred from the hair to the surface of the balloon.

As a result, when the balloon is detached from the hair, it will have an excess of negative charge (due to the acquired electrons).

Then, the balloon is placed in contact with the non-conducting wall.

The non-conducting wall is initially neutral (equal number of positive and negative charges).

Because the wall is made of a non-conducting material (=isolant), the charges cannot move easily through it. Therefore, even though the charges on the wall feel a force due to the presence of the electrons in the balloon, they will not redistribute along the wall.

Therefore, the charges on the wall will remain equally distributed, as shown in figure A.

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Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy?
puteri [66]

Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy would be 812.5 Joules.

<h3>What is mechanical energy?</h3>

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

As given in the problem we have to calculate the Kinetic energy of the Jemima,

Kinetic energy = 1/2 ×mass×velocity²

                        =0.5×65×5²

                        =812.5 Joules

Thus, the kinetic energy of the Jemima would be 812.5 Joules.

To learn more about mechanical energy, refer to the link;

brainly.com/question/12319302

#SPJ1

4 0
1 year ago
The trachea splits into two branches called larynx true or false<br> pls answer somebodyyyyyyy
kirill115 [55]

Answer:

False

Explanation:

The trachea divides into left and right air tubes called bronchi, which connect to the lungs. Within the lungs, the bronchi branch into smaller bronchi and even smaller tubes called bronchioles.

Hope this helps :)

7 0
3 years ago
__________ occurs when a substance emits light after absorbing light or other electromagnetic radiation of a different wavelengt
LekaFEV [45]

The answer Is C i hope this is helpfull

3 0
3 years ago
A stereo speaker is rated at P1000 = 52 W of output at 1000 Hz. At 20 Hz, the sound intensity level LaTeX: \betaβ decreases by 1
baherus [9]

Answer:

The  value of the power is   P_c  =  38.55 \  W

Explanation:

From the question we are told that

   The  power  rating P_{1000} =P_b=  52 \  W

    The frequency is  f = 1000 \  Hz

    The  frequency at which the sound intensity decreases  f_k  =  20 \  Hz

     The decrease in intensity is by \beta  =  1.3 dB

Generally the  initial intensity of the speaker  is mathematically represented as

     \beta_1 =  10 log_{10} [\frac{P_b}{P_a} ]

Generally the intensity of the speaker after it has been decreased is

       \beta_2 =  10 log_{10} [\frac{P_c}{P_a} ]

So

\beta_1-\beta_2 =  10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]

=>  \beta =  10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3

=>  \beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3

=>  \beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3

=> 10log_{10} [\frac{P_b}{P_c} ] = 1.3

=> log_{10} [\frac{P_b}{P_c} ] = 0.13

taking atilog of both sides

[\frac{P_b}{P_c} ] = 10^{0.13}      

=>[\frac{52}{P_c} ] = 10^{0.13}      

=>  P_c  =  \frac{52}{1.34896}

=>   P_c  =  38.55 \  W

   

3 0
3 years ago
What is the velocity of a penny dropped from the roof after 5 seconds?
Ksivusya [100]

Answer:

49 m/s

Explanation:

Acceleration = velocity / time

You should know accleration due to gravity is 9.8 m/s^2 and you're given t = 5, so you can solve for velocity:

9.8 = v / 5

v = 49

4 0
3 years ago
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