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il63 [147K]
1 year ago
7

The rotational inertia of an object depends not just upon the mass of the object but the mass distribution. What sort of mass di

stribution gives a large rotational inertia?
Physics
1 answer:
Oksanka [162]1 year ago
6 0

The object whose mass is distributed farther away from the axis of rotation will have greater rotational inertia.

<h3>What is rotational inertia?</h3>

Rotational inertia is a property of any object which can be rotated. It depends on mass and radius of the object.

<h3>Mass distribution of rotational inertia</h3>

The rotational inertia of two objects with the same mass and radius, is different when the mass distribution is different.

Thus, the object whose mass is distributed farther away from the axis of rotation will have greater rotational inertia.

Learn more about rotational inertia here: brainly.com/question/14001220

#SPJ1

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A skater extends her arms horizontally, holding a 5-kg mass in each hand. She is rotating about a vertical axis with an angular
sp2606 [1]

Answer:

1.98 rev/s

Explanation:

m  = mass attached to each hand = 5 kg

r_{i} = initial distance of masses in each hand = 1 m

r_{f} = final distance of masses in each hand = 0.1 m

I = moment of inertia of body = 5 kgm²

I_{i} = initial total moment of inertia = I + 2 mr_{i}^{2}

w_{i} = initial angular velocity = 1 rev/s

I_{f} = final total moment of inertia = I + 2 mr_{f}^{2}

w_{f} = final angular velocity = ?

Using conservation of angular momentum

I_{i} w_{i} = I_{f} w_{f}

(I + 2 mr_{i}^{2}) w_{i} = (I + 2 mr_{f}^{2}) w_{f}

(5 + 2 (5) (1)^{2}) (1) = (5 + 2 (5) (0.1)^{2}) w_{f}

w_{f} = 2.94 rev/s

3 0
3 years ago
Read 2 more answers
A 250 g air-track glider is attached to a spring with springconstant 4.0 N/m. Th damping constant due to air resistance is0.015
vaieri [72.5K]

Answer:

33.33 seconds

Explanation:

N=\dfrac{1}{e}N_0

N_0 = Initial length pulled = 20 cm

b = Damping constant = 0.015 kg/s

k = Spring constant = 4 N/m

m = Mass of glider = 250 g

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.25}{4}}\\\Rightarrow T=1.57079632679\ s

Using exponential decay formula

N=N_0e^{\dfrac{-bt}{m}}

Final amplitude = Initial times decay

\dfrac{1}{e}0.2=0.2e^{\dfrac{-0.015t}{2\times 0.25}}\\\Rightarrow 0.2=0.2e^{\frac{-0.015t}{2\cdot \:0.25}+1}\\\Rightarrow e^{\frac{-0.015t}{2\cdot \:0.25}+1}=1\\\Rightarrow \ln \left(e^{\frac{-0.015t}{2\cdot \:0.25}+1}\right)=\ln \left(1\right)\\\Rightarrow \left(\frac{-0.015t}{2\cdot \:0.25}+1\right)\ln \left(e\right)=\ln \left(1\right)\\\Rightarrow \frac{-0.015t}{2\cdot \:0.25}+1=\ln \left(1\right)\\\Rightarrow -\frac{0.015t}{0.5}=-1\\\Rightarrow -0.000225t=-0.0075\\\Rightarrow t=33.33\ s

The time taken is 33.33 seconds

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3 years ago
What is a continuous range of a single feature such as a wave lengt
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<span>I think you're looking for "spectrum".</span>



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3 years ago
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V = I*R
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(2) The answer is attached in image form down below(please find attachment)
(3) </span>The answer is attached in image form down below(please find attachment)

(4) <span>Renewable energy is the energy which is generated from the natural sources i.e. sun, tides, wind etc. Examples are: Solar Energy, Wind energy( windmill) etc. for electricity generation.
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1) It is available in abundant quantity.
2) It is free to use.
3) It has </span><span>low carbon emissions, therefore it is considered as green and environment friendly.
Disadvantages of Renewable Energy:
1) It is not easy to setup plants and machinery for renewable energy.
2) Initial costs for setting up those plants and machinery is quite high.
3) The energy from the natural sources is not available 24/7. In Solar energy case, energy </span><span>can be used during the day time and not during night or rainy season etc.
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Non-Renewable energy is energy which is taken from the sources that are available on the earth in limited quantity. Sources may be <span>fossil fuels, natural gas, oil and coal etc.
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Disadvantages:
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Now you should judge all by yourself which is the better energy source.
-i

</span>

8 0
3 years ago
A wheel that was initially spinning is accelerated at a constant angular acceleration of 5.0 rad/s^2. After 8.0 s, the wheel is
notka56 [123]

Answer:

a)  Initial angular speed = 30 rad/s

b) Final angular speed = 70 rad/s        

Explanation:

a) We have equation of motion s = ut + 0.5at²

    Here s = 400 radians

              t = 8 s

              a = 5 rad/s²

    Substituting

             400 = u x 8 + 0.5 x 5 x 8²

              u = 30 rad/s

   Initial angular speed = 30 rad/s

b) We have equation of motion v = u + at

     Here u = 30 rad/s

               t = 8 s

              a = 5 rad/s²  

    Substituting

             v = 30 + 5 x 8 = 70 rad/s    

   Final angular speed = 70 rad/s        

8 0
3 years ago
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