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tankabanditka [31]
3 years ago
14

One possible explanation for a galaxy's type invokes the angular momentum of the protogalactic cloud from which it formed. Suppo

se a galaxy forms from a protogalactic cloud with a lot of angular momentum. Assuming its type has not changed as a result of other interactions, we'd expect this galaxy to be ______.
Physics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

A spiral galaxy

Explanation:

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At the lowest point in a vertical dive (radius = 0.58 km), an airplane has a speed of 300 km/h which is not changing. Determine
murzikaleks [220]

Answer:

The centripetal acceleration is a = 11.97 \ m/s^2

Explanation:

From the question we are told that

     The radius  is r =  0.58 \ km =  0.58 * 1000  =  580 \ m

      The speed is v  = 300\ km /hr =  \frac{300 *1000}{1 * 3600 }  =  83.33 \ m/s

The centripetal acceleration of the pilot is mathematically represented as

       a =  \frac{v^2 }{r}

substituting  values

      a =  \frac{(83.33)^2 }{580}

     a = 11.97 \ m/s^2

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3 years ago
What does a star turn hydrogen into?
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Helium

Explanation:

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What evidence would you observe if the law of conservation of mass is obeyed when mixing two solutions?​
Marianna [84]

Answer:

You should have noticed that the number of atoms in the reactants is the same as the number of atoms in the product. The number of atoms is conserved during the reaction. However, you will also see that the number of molecules in the reactants and products are not the same.

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3 years ago
A proposed space elevator would consist of a cable stretching from the earth's surface to a satellite, orbiting far in space, th
NISA [10]

To solve this problem we will apply the concepts related to energy conservation. Here we will use the conservation between the potential gravitational energy and the kinetic energy to determine the velocity of this escape. The gravitational potential energy can be expressed as,

PE= \frac{GMm}{d}

The kinetic energy can be written as,

KE= \frac{1}{2} mv^2

Where,

G = 6.67*10^{-11}m^3/kg\cdot s^2Gravitational Universal Constant

m = 5.972*10^{24}kg Mass of Earth

h = 56*10^6m  Height

r = 6.378*10^6m Radius of Earth

From the conservation of energy:

\frac{1}{2} mv^2 = \frac{GMm}{d}

Rearranging to find the velocity,

v = \sqrt{\frac{2Gm}{d}} \rightarrow  Escape velocity at a certain height from the earth

If the height of the satellite from the earth is h, then the total distance would be the radius of the earth and the eight,

d = r+h

v = \sqrt{\frac{2Gm}{r+h}}

Replacing the values we have that

v = \frac{2(6.67*10^{-11})(5.972*10^{24})}{6.378*10^6+56*10^6}

v = 3.6km/s

Therefore the escape velocity is 3.6km/s

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3 years ago
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