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tankabanditka [31]
3 years ago
14

One possible explanation for a galaxy's type invokes the angular momentum of the protogalactic cloud from which it formed. Suppo

se a galaxy forms from a protogalactic cloud with a lot of angular momentum. Assuming its type has not changed as a result of other interactions, we'd expect this galaxy to be ______.
Physics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

A spiral galaxy

Explanation:

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Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 2.4
NeX [460]

When person is observing destructive interference at 0.20 m distance from the equidistant position then we can say that path difference must be equal to half of the wavelength

now we will have

\frac{\lambda}{2} = \frac{yd}{L}

now we know that

y = 0.20 m

d = 2.4 m

L = 10 m

now here we have

\frac{\lambda}{2} = \frac{0.20\times 2.4}{10}

\lambda = 0.096 m

now frequency of wave is given as

f = \frac{v}{\lambda}

f = \frac{343}{0.096} = 3573 Hz

5 0
3 years ago
You want the current amplitude through a inductor with an inductance of 4.70 mH (part of the circuitry for a radio receiver) to
goldenfox [79]

Answer:

f = 1.69*10^5 Hz

Explanation:

In order to calculate the frequency of the sinusoidal voltage, you use the following formula:

V_L=\omega iL=2\pi f i L         (1)

V_L: voltage = 12.0V

i: current  = 2.40mA = 2.40*10^-3 A

L: inductance = 4.70mH = 4.70*10^-3 H

f: frequency = ?

you solve the equation (1) for f and replace the values of the other parameters:

f=\frac{V_L}{2\pi iL}=\frac{12.0V}{2\pi (2.4*10^{-3}A)(4.70*10^{-3}H)}=1.69*10^5Hz      

The frequency of the sinusoidal voltage is f

3 0
3 years ago
What type of accidents are among the most common cause of serious work related injuries and deaths
Bezzdna [24]
Trips/slips/falls are among the most common types of work related injuries and/or deaths.
7 0
3 years ago
Read 2 more answers
An elevator is moving is an upwards
Minchanka [31]

Answer:

The elevator's free-body diagram has three forces, the force of gravity, a downward normal force from you, and an upward force from the tension in the cable holding the elevator. The combined system of you + elevator has two forces, a combined force of gravity and the tension in the cable.

Explanation:

6 0
3 years ago
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
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