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Butoxors [25]
3 years ago
6

A 2,000 kg car is moving at 15m/s when it collides with a 1200kg car sitting still. Briefly compare the impulse imparted on the

1200kg car by the 2000 kg car to the impulse on the 2000 kg car by the 1200 kg car which car under goes the greater change in momentum
Physics
2 answers:
mihalych1998 [28]3 years ago
8 0

Answer:

Explanation:

Given:

mass of car 1 = 2000 kg

speed of car 1 = 15 m/s

mass of car 2 = 1200 kg

car 2 is initially at rest.

Impulse (F Δt) = change in momentum = Δ(mv)

Change in Momentum depends on the mass and velocity.

When car 1 collides with car 2, car 1 would under go greater change in the momentum because it has greater mass and initial velocity while car 2 has smaller mass and is initially at rest.

I am Lyosha [343]3 years ago
4 0

impulse = F × t

The greater the impulse exerted on something, the greater will be the change in momentum.

impulse = change in momentum

Ft = ∆(mv)

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4 0
2 years ago
The rhinestones in costume jewelry are glass with index of refraction 1.50. To make them more reflective, they are often coated
Sedaia [141]

Answer:

60

Explanation:

According to the given question, the computation of minimum coating thickness is shown below:-

The condition for constructive interference is

2t_{min} = (m + \frac{1}{2} )\times \frac{\lambda}{^nmateral}

= (0 + \frac{1}{2} )\times \frac{\lambda}{^nmateral}

t = \frac{\lambda}{4n}

Now we will put the values to the above formula to reach the answer

= \frac{480nm}{4\times 2.0}

= 60

Therefore we simply applied the above formula to determine the minimum coating thickness

6 0
3 years ago
Tính lực tương tác giữa 2 điện tích q1=4.10^-6C và q2=-3.10^-6C cách nhau một 3cm đặt trong dầu hoả = 2
olga2289 [7]

Explanation:

decimal diamond ml dias and ka n t u t a n mo papa mo

4 0
2 years ago
The 2.5-Mg van is traveling with a speed of 100 km>h when the brakes are applied and all four wheels lock. If the speed decre
Andrew [12]

Answer:

0.34

Explanation:

2.5 Mg = 2500 kg

The change in speed from 100 km/h to 40 km/h is

\Delta v = 100 - 40 = 60 km/h = 60 * 1000 / (60 * 60) = 16.67 m/s

The deceleration caused by friction force is the change in speed per unit of time

a = \Delta v / \Delta t = 16.67 / 5 = 3.33 m/s^2

Using Newton 2nd law we can calculate the friction force that caused this deceleration:

F = ma = 2500 * 3.33 = 8333 N

Let g = 9.8m/s2. Friction force is the product of normal (gravity) force and friction coefficient

F = mg\mu

8333 = 2500*9.8\mu

\mu = \frac{8333}{2500 * 9.8} = 0.34

4 0
3 years ago
The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is
kiruha [24]

Answer:

Explanation: Here we have given a direct equation . There for no need to worry .

P = I²×R

P = (12)² ×100

P = 14400W = 14.4 kW

For second one

P = I² ×R

200 = I²×150

I = √200/150

I = 1.15 A

5 0
3 years ago
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