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lys-0071 [83]
3 years ago
11

Definition of reactant

Chemistry
1 answer:
Alecsey [184]3 years ago
5 0

<em>Noun </em>

a substance that takes part in and undergoes change during a reaction.

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Explain the arrangement of particles in solids, liquids and gases.​
Alex787 [66]
Solids are tightly compacted
Liquids are medium
And gases are very spaced and floating around
6 0
3 years ago
Calculate the density of a solid if it has a mass of 8.47 g and a volume of 3.24 cms.
gtnhenbr [62]

Answer:

Density =2.614g/cms

Explanation:

Density = mass/volume

Density= 8.47g/3.24cms

3 0
3 years ago
Help!!
anyanavicka [17]

I believe this a PV = nRT question whereas

you re write the formula and solve for volume

V = nRT/ P

then you input the values

P= pressure constant

V= x

n = moles = 0.2540

R = gas constant should be 8.314J mol

T = C degrees + 273.15 = K

solve for voume

make sure all units match

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7 0
3 years ago
Cans of regular soda have volumes with a mean of 14.5 oz and a standard deviation of 0.18 oz. What is the maximum "usual" value
tangare [24]

Answer:

14.68 oz

Explanation:

The mean volume is the average volume of all the regular soda cans put together; 14.5 oz. The standard deviation 0.18 oz is the maximum deviation from the mean. It can be 14.5-0.18= 14.32 oz which is the usual minimum or 14.5 + 0.18=14.68 oz which is the usual maximum

4 0
3 years ago
A current of 5. 68 a is passed through a Fe(NO3)2 solution. How long, in hours, would this current have to be applied to plate o
daser333 [38]

There are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

Calculation ,

Given ; Current ( I ) = 5. 68 A

In Fe(NO_{3} )_{2} , the valancy of Fe is +2 .

2 moles of e^{-} are required for the decomposition of 1 mole of Fe .

7. 20 g  of Fe in moles  = 7. 20 g /55.845 g/mol =0.12 mole

x moles of  e^{-} are required for the decomposition of 0.128 mole of Fe .

moles of   e^{-} are required = 0.256 moles

Charge on 1 mole  of   e^{-} = 96500 C

Charge on 0.256  mole  of   e^{-} = 24704 C

Current ( I )= Q/t  

t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr

Therefore , there are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

To learn more about iron

brainly.com/question/18500540

#SPJ4

8 0
1 year ago
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