Answer : The correct answer is 1) AlCl₃ - CH₃Cl 2) HNO₃ -H₂SO₄ at room temperature 3) Fuming HNO₃ -H₂SO₄ at 90-100 ⁰ C heat .
I think this reaction is forming 2,4,6- trinitrotoluene from benzene, since the product is not mentioned. Following are the steps to convert Benzene to 2,4,6 trinitrotoluene .
Step 1: Conversion of Benzene to Toluene .
Benzene can be converted to toluene by Friedel Craft Alkylation of benzene . In this reaction reagent AlCl₃ and Ch3Cl is used . Electrophile CH³⁺ is produced which attached on carbon of benzene and formation of Toluene and HCl occur.

Step 2 : Conversion of Toluene to dinitrotoluene.
Dinitritoluene is prepared from toluene by Nitration . This reaction uses Electrophilic substitution mechanism . The reagents used are HNO₃ and H₂SO₄ at room temperature . These reagents produces NO₂⁺ ( nitronium ion ), a electrophile which attacks on C2 and C4 Carbon atoms of Toluene.
Toluene 
Step 3) Conversion of Dinitro toluene to trinitrotoluene.
This reaction is extended nitration of toluene . Further nitration is done in extreme condition . The temperature of reaction is increased to 90- 100 ⁰ C . Due to which there is more production of NO²⁺ ion occurs from HNO₃ -H₂SO₄ and they attack on C6 carbon atom of dinitrotoluene which forms 2,4,6- trinitrotoluene.
Dinitrotoluene 
So over all reaction uses three reagents in order :

six commonly recognised metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium. Five elements are less frequently so classified: carbon, aluminium, selenium, polonium, and astatine.
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Answer:
hand picking
Explanation:
as stone is bigger in size we can see them with our eyes so we can handpick it
Answer:
46.0g of Iron are produced
Explanation:
Based on the chemical reaction:
FeO(l) + Mg(l) → Fe(l) + MgO(s)
<em>1 mole of Iron (II) oxide reacts per mole of Mg to produce 1 mole of iron</em>
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To solve this question we need to convert each mass of reactant to moles using its respectives molar masses in order to find limitng reactant. Moles of limiting reactant = Moles of iron produced:
<em>Moles FeO (Molar mass: 71.85g/mol):</em>
80.0g * (1mol / 71.85g) = 1.11moles FeO
<em>Moles Mg (Molar mass: 24.305g/mol)</em>
20.0g * (1mol / 24.305g) = 0.823 moles Mg
As moles of Mg < Moles FeO, Mg is limiting reactant and the moles of Fe are 0.823 moles.
The mass of Iron produced is:
0.823 moles Fe * (55.845g/mol) =
46.0g of Iron are produced