Question

A bus start from rest. If the acceleration of bus is 0.5 m/s square. what will be its velocity at the end of 2 minutes?what will be the distance cover?​

Answer 1

Answer:

$\fbox {Velocity = 60 m/s, Distance = 3600 m}$

Explanation:

Part (i) : Velocity at end of 2 minutes

Equation used ⇒ $\boxed {v = u + at}$

⇒ t = 2 minutes = 2 x 60 = 120 seconds

⇒ v = 0 + (0.5)(120)

⇒ v = 60 m/s

Part (ii) : Distance covered

Equation used ⇒ $\boxed {S = \frac{v^{2}-u^{2}}{2a}}$

⇒ S = (60)² - (0)² / 2(0.5)

⇒ S = 3600 m

Answer 2

Answer:

3586

Explanation:

by using formula s=it+0.5at^2