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3 years ago

13

The part of the cerebrum that controls voluntary movements is located in the _______ lobe. A. frontal B. parietal C. temporal D.

occipital

2 answers:

uranmaximum [27]3 years ago

5 0

The part of the cerebrum that controls Voluntary movements is located in the Frontal lobe.

Ksenya-84 [330]3 years ago

5 0

I believe the answer is frontal

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If an astronaut throws an object in space, the object’s speed will _____

BigorU [14]

The object's speed will not change.

In fact, after the astronaut throws the object, no additional forces will act on it (since the object is in free space). According to Newton's second law:
$\sum F=ma$
where the first term is the resultant of the forces acting on the body, m is the mass of the object and a its acceleration, we see that if no forces act on the object, then the acceleration is zero. Therefore, the acceleration of the object is zero, and its velocity remains constant.

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3 years ago

2 ways to change frictional force between 2 objects

Zanzabum

In order to change the frictional force between two solid surfaces, it can be changed by shorter distances and by the amount of weight it has or the amount of force that is pushing that object to go however distance it can.

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3 years ago

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A box falls out of a stationary helicopter hovering 135 m above the ground. How long will it take to hit the ground?

Marrrta [24]

We have the equation of motion $s = ut + \frac{1}{2} at^2$ , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here displacement = 135 m, Initial velocity = 0 m/s, acceleration = 9.81 $m/s^2$

Substituting

$135 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2 =135\\ \\ t =5.25 seconds$

A box falls out of a stationary helicopter hovering 135 m above the ground will take 5.25 seconds to reach the ground.

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3 years ago

What is the coefficient of friction between the skates and the ice?

natta225 [31]

The coefficient of friction is 0.051

Explanation:

The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v^2 - u^2 = 2as$

where:

v = 0 is the final velocity of the skater (he comes to a stop)

u = 10.0 m/s is his initial velocity

a is the acceleration

$s=1.0\cdot 10^2 m = 100 m$ is the distance he travels before stopping

Solving for a, we find the acceleration of the skater:

$a=\frac{v^2-u^2}{2s}=\frac{0-10.0^2}{2(100)}=-0.5 m/s^2$

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

$F= ma = -\mu mg$

where

$-\mu mg$ is the force of friction

m is the mass of the skater

$\mu$ is the coefficient of friction

$a=-0.5 m/s^2$ is the acceleration

$g=9.8 m/s^2$ is the acceleration of gravity

Solving for $\mu$ , we find the coefficient of friction:

$\mu = -\frac{a}{g}=-\frac{-0.5}{9.8}=0.051$

Learn more about friction:

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3 years ago

"Response to stimulus" refers to

nlexa [21]

I think is reaction
STIMULUS: In physiology, a stimulus is a detectable change in the internal or external environment. When a stimulus is applied to a sensory receptor, it elicits or influences a reflex via stimulus transduction.

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3 years ago