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3 years ago

these questions confuse me. i think I know the answer but I'm not sure. this is density/hydraulic devices. help?

Physics

2 answers:

Bad White [126]3 years ago

8 0

It is hydraulic. The key is to remember that the pressure will be constant through the whole liquid thus the force requuired on the left side will be much less and proportional to the difference in area of the right and the left. Do you need actual calculations or can you figure it out from this? Think Pascal's principle

Anna11 [10]3 years ago

5 0

Had a quick look at the q, here's some guesswork .. apologies in advance for the "humour" ...
pressure in liquid is elephant divided by area she's (After the song about an elephant ... ) standing on.
45000/250,000 N/cm^2=0.18
p=F/A. F=pA. p=0.18, A=500. F=0.18x500N
Elle La Fonte + Platform =45,000N

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An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it

steposvetlana [31]

Answer:

μs = 0.36

Explanation:

While the drum is rotating, the riders, in order to keep in a circular movement, are accelerated towards the center of the drum.
This acceleration is produced by the centripetal force.
Now, this force is not a different type of force, is the net force acting on the riders in this direction.
Since the riders have their backs against the wall, and the normal force between the riders and the wall is perpendicular to the wall and aiming out of it, it is easily seen that this normal force is the same centripetal force.
In the vertical direction, we have two forces acting on the riders: the force of gravity (which we call weight) downward, and the friction force, that will oppose to the relative movement between the riders and the wall, going upward.
When this force be equal to the weight, it will have the maximum possible value, which can be written as follows:

$F_{frmax} = \mu_{s}* F_{n} = m * g (1)$

where μs= coefficient of static friction (our unknown)

As we have already said Fn = Fc.
The value of the centripetal force, is related with the angular velocity ω and the radius of the drum r, as follows:

$F_{n} = m* \omega^{2} * r (2)$

Replacing (2) in (1), simplifying and rearranging terms, we can solve for μs, as follows:

$\mu_{s} = \frac{g}{\omega^{2} r} (3)$

Prior to replace ω for its value, is convenient to convert it from rev/min to rad/sec, as follows:

$\omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)$

Replacing g, ω and r in (3):
$\mu_{s} = \frac{g}{\omega^{2} r} = \frac{9.8m/s2}{(2.72rad/sec)^{2} *3.7 m} = 0.36 (5)$

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3 years ago

Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.

Annette [7]

Answer:

option (D)

Explanation:

Here initial rotation speed is given, final rotation speed is given and asking for time.

If we use

A) θ=θ0+ω0t+(1/2)αt2

For this equation, we don't have any information about the value of angular displacement and angular acceleration, so it is not useful.

B) ω=ω0+αt

For this equation, we don't have any information about angular acceleration, so it is not useful.

C) ω2=ω02+2α(θ−θ0)

In this equation, time is not included, so it is not useful.

D) So, more information is needed.

Thus, option (D) is true.

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3 years ago

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san4es73 [151]

Answer: We can define the solar constant as a measure of the luminous flux density.

Explanation:

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Sladkaya [172]

Answer:

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Explanation:

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3 years ago

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vlada-n [284]

Answer: Friction

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