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2 years ago

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Object 1 has a mass of 99.2 kg. Object 2 has a mass of 42.3 kg. If the 2 object pust against each other, what will be the speed

of the 2nd object

1 answer:

Vlad1618 [11]2 years ago

7 0

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There are two parallel conductive plates separated by a distance d and zero potential. Calculate the potential and electric fiel

taurus [48]

Answer:

The total electric potential at mid way due to 'q' is $\frac{q}{4\pi\epsilon_{o}d}$

The net Electric field at midway due to 'q' is 0.

Solution:

According to the question, the separation between two parallel plates, plate A and plate B (say) = d

The electric potential at a distance d due to 'Q' is:

$V = \frac{1}{4\pi\epsilon_{o}}.\frac{Q}{d}$

Now, for the Electric potential for the two plates A and B at midway between the plates due to 'q':

For plate A,

$V_{A} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{\frac{d}{2}}$

Similar is the case with plate B:

$V_{B} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{\frac{d}{2}}$

Since the electric potential is a scalar quantity, the net or total potential is given as the sum of the potential for the two plates:

$V_{total} = V_{A} + V_{B} = \frac{1}{4\pi\epsilon_{o}}.q(\frac{1}{\frac{d}{2}} + \frac{1}{\frac{d}{2}}$

$V_{total} = \frac{q}{4\pi\epsilon_{o}d}$

Now,

The Electric field due to charge Q at a distance is given by:

$\vec{E} = \frac{1}{4\pi\epsilon_{o}}.\frac{Q}{d^{2}}$

Now, if the charge q is mid way between the field, then distance is $\frac{d}{2}$ .

Electric Field at plate A, $\vec{E_{A}}$ at midway due to charge q:

$\vec{E_{A}} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{(\frac{d}{2})^{2}}$

Similarly, for plate B:

$\vec{E_{B}} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{(\frac{d}{2})^{2}}$

Both the fields for plate A and B are due to charge 'q' and as such will be equal in magnitude with direction of fields opposite to each other and hence cancels out making net Electric field zero.

3 0

3 years ago

The world record for the 100.0 meter dash is 9.580 seconds. Find the speed of the runner in miles per hour.

grigory [225]

Answer:

233.1 miles per hours

Explanation:

Speed: This is defined as the ratio of distance to time. The S.I unit of speed is m/s. speed is a vector quantity because it can only be represented by magnitude only. Mathematically, speed can be expressed as,

S = d/t ....................... Equation 1

Where S = speed of the runner, d = distance covered, t = time.

Given: d = 100 meter , t = 9.580 seconds

Conversion:

If, 1 meter = 0.00062 miles

Then, 100 meters = (0.00062×100) miles = 0.62 miles.

Also

If, 3600 s = 1 h

Then, 9.580 s = (1×9.580)/3600 = 0.00266 hours.

Substitute into equation 1

S = 0.62/0.00266

S = 233.1 miles per hours.

Hence the runner speed is 233.1 miles per hours

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3 years ago