The approximate molar mass of lauryl alcohol is 183 g/mol.
As per Raoult's law:

Tb = the freezing point of benzene (5.5oC), Ts = the freezing point of the solution, K = the cryoscopic constant (5.12 K*kg/mol for benzene), and Cm = the molality of the solution.
/M
=
where ml is the mass of lauryl alcohol and ms is the mass of the solvent.
=K
/M
Therefore, M=
=
=183 g/mol.
<h3>Lauryl alcohol </h3>
An organic substance called lauryl alcohol is created industrially from coconut or palm kernel oil. It is an alcoholic fat. The use of sodium lauryl sulfate and other sulfate esters of lauryl alcohol as surfactants is extremely common. In shampoos, sodium laureth sulfate, ammonium laureth sulfate, and sodium lauryl sulfate are all utilized. Lauryl alcohol has a floral scent and is flavorless and colorless. In addition to being a flavor-enhancing food additive, lauryl alcohol is also used to create medicines, lubricating lubricants, surfactants, and monolithic polymers. Lauryl alcohol is a kind of emollient used in cosmetics. Lauryl alcohol, a significant scent, and 1-bromododecane, an alkylating agent used to increase the lipophilicity of organic molecules, are both precursors to Lauryl alcohol.
A solution of 5. 00 g of lauryl alcohol in 0. 100 kg of benzene freezes at 4. 1°c. what is the approximate molar mass of lauryl alcohol?
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The final volume of the diluted solution that initially has a volume 10.0 mL sample and concentration of 5.00M HCl is 232.6mL.
<h3>How to calculate volume?</h3>
The volume of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
- C1 = initial concentration
- C2 = final concentration
- V1 = initial volume
- V2 = final volume
10 × 5 = 0.215 × V2
50 = 0.215V2
V2 = 50/0.215
V2 = 232.6mL
Therefore, the final volume of the diluted solution that initially has a volume 10.0 mL sample and concentration of 5.00M HCl is 232.6mL.
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Answer:
the stream contains more water and moves faster
Explanation: