Help me label the equation.. please?

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

$1810.04571428[mL]=V_2$

Adjusting for significant figures, this gives $V_2=1810[mL]$

4 0

2 years ago

How many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas?

ASHA 777 [7]

How many moles of water at produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas the answer is D

5 0

3 years ago

Define the term inertia

n200080 [17]

Answer:

Explanation:

Enertia is an integral part of Newton's first law of motion.

It is the tendency of an object to stay at rest or to continue moving until and unless any external unbalanced force, (like, applied force or force of tension or frictional force ) is applied to either move it from rest or change its speed(in other words, accelerate it!!).

Example below, is of ball at rest (fig1) and if this ball is moving straight on a frictionless surface(like ice) it will keep moving!! until, we push it or pull it.

5 0

4 years ago

What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?

Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

5 0

3 years ago

Why aren't flowers sold at a monastery math worksheet answers?

maria [59]

1) x/9 + 16 = 5.

a) x/9 + 16 - 16 = 5 -16; subtraction.

b) x/9 = -11; simplifying.

c) x/9 · 9 = -11 · 9; multiplication.

d) x = -99; simplifying.

2) 5 · (2a - 3) = 60.

a) 10a - 15 = 60; distributive.

b) 10 - 15 + 15 = 60 + 15; addition.

c) 10a = 75; simplifying.

d) 10a ÷ 10 = 75 ÷ 10; commutative.

e) a = 7.5; simplifying.

3) 4 n + (7 + n) = 52.

a) 4n + (n + 7) = 52; commutative.

b) ( 4n + n) + 7 = 52; associative.

c) 5n + 7 = 52; combining.

d) 5n + 7 - 7 = 52 - 7; subtraction.

e) 5n = 45; simplifying.

f) 5n ÷ 5 = 45 ÷ 5; division.

g) n = 9; simplifying.

4) 8t - 3 · (4t + 2) = 16.

a) 8t - 12 t - 6 = 16; distributive.

b) -4 t - 6 = 16; combining.

c) - 4 t - 6 + 6 = 16 + 6; addition.

d) -4t = 22; simplifying.

e) -4t ÷ (-4) = 22 ÷ (-4); division.

f) t = -5.5; simplifying.

This is the question I found on internet.

8 0

3 years ago

Read 2 more answers