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2 years ago

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The influent BOD5 to a primary settling tank is 345 mg/L. The average flow rate is 0.050 m3/s. If the BOD5 removal efficiency is

30%, how many kilograms of BOD5 are removed in the primary settling tank each day?

1 answer:

allochka39001 [22]2 years ago

7 0

The kilograms of BOD5 that are removed in the primary settling tank each day is 447.12 kg.

<h3>How to calculate the value?</h3>

The BOD5 removed in the primary settling tank each day will be:

= efficiency * influent * average flow rate*24*60*60

The average flow rate is 0.050 m3/s and the BOD5 removal efficiency is 30%,

Influent = 0.345 g/L = 0.000345 kg/L

BOD5 removed in the primary settling tank each day will be:

= 0.3*50*0.000345*24*60*60

= 447.12 kg

Learn more about settling tank on:

brainly.com/question/27736862

#SPJ1

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Explanation:

Given

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<em>Hence, the resultant force is 200N</em>

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