Answer:
The specific heat capacity of substance A is 1.16 J/g
Explanation:
The substances A and B come to a thermal equilibrium, therefore, the heat given by the hotter substance B is absorbed by the colder substance A.
The equation becomes:
Heat release by Substance B = Heat Gained by Substance A
The heat can be calculated by the formula:
Heat = mCΔT
where,
m = mass of substance
C = specific heat capacity of substance
ΔT = difference in temperature of substance
Therefore, the equation becomes:
(mCΔT) of A = (mCΔT) of B
<u>FOR SUBSTANCE A:</u>
m = 6.01 g
ΔT = Final Temperature - Initial Temperature
ΔT = 46.1°C - 20°C = 26.1°C
C = ?
<u>FOR SUBSTANCE B:</u>
m = 25.6 g
ΔT = Initial Temperature - Final Temperature
ΔT = 52.2°C - 46.1°C = 6.1°C
C = 1.17 J/g
Therefore, eqn becomes:
(6.01 g)(C)(26.1°C) = (25.6 g)(1.17 J/g)(6.1°C)
C = (182.7072 J °C)/(156.861 g °C)
<u>C = 1.16 J/g</u>
