Answer:
Considering the guidelines of this exercise.
The pieces produced per month are 504 000
The productivity ratio is 75%
Explanation:
To understand this answer we need to analyze the problem. First of all, we can only produce 2 batches of production by the press because we require 3 hours to set it up. So if we rest those 6 hours from the 8 of the shift we get 6, leaving 2 for an incomplete bath. So multiplying 2 batches per day of production by press we obtain 40 batches per day. So, considering we work in this factory for 21 days per month well that makes 40 x 21 making 840 then we multiply the batches for the pieces 840 x 600 obtaining 504000 pieces produced per month. To obtain the productivity ratio we need to divide the standard labor hours meaning 6 by the amount of time worked meaning 8. Obtaining 75% efficiency.
Answer:
clothes iron its 3rdyeyeyey
Explanation:
clothes iron its 3rd
clothes iron its 3rd
clothes iron its 3rd
clothes iron its 3rd
clothes iron its 3rd
btw quaotra
yesss
Technician A is correct when he says that the emissions label contains the refrigerant charge amount while Technician B is wrong.
<h3>What is emission label?</h3>
An emissions label is known to be a kind of sticker that is often used by EPA to have manufacturers show that their non-road engines meet the needed emission requirements.
In terms of AC system, they are found under the hood of the AC unit and as such, Technician A is correct when he says that the emissions label contains the refrigerant charge amount while Technician B is wrong.
Learn more about refrigerant charge from
brainly.com/question/12823745
#SPJ1
It is High system pressure
Answer:
4.18 J/KgK
Explanation:
Equilibrium point is reached when
m₁*c₁(T₁-T) = m₂*c₂(T -t₂)
m1 = 20
c1 = 0.5
T1 = 450
m2 = 150 kg
c2 = 2.6
T2 = 50
putting these values into the formula
20*0.5 (450-T) = 150*2.6(T - 50)
4500 - 10T = 390T<em> - 19500</em>
4500 + 19500 = 390T + 10T
24,000 = 400T
T = 24000/400
= 60⁰C
ΔSmetal = m1*c1In[t + 273]/[T1+273]
= 20*0.5 In (60+273)/450+273
= 10 ln(333/723)
= 10 * -0.7752
= -7.752
ΔS/oil =
m2*s2(60 + 273)/50 + 273)
= 150*2.6ln(333/323)
= 390 * 0.03048
= 11.88j/KgK
Δ<em>total = -7.7+11.8</em>
<em>= </em><em>4.18J/KgK</em>
this is the enthropy change
