Answer:
Explanation:
Since we are considering electron and hole drift velocities, then electric field E will have to be taken into consideration as well.
Where E = V/d...... 1
Drift velocity (u) = -μE. For electron.... 2
Drift velocity (v) = μE. For hole...... 3
Given that : V = 5V and d = 10 um (micro meter)
From equation 1
E = V/d
E = 5V/10×10^-4cm
E = 5V ÷1/1000
E = 5×1000
E = 5000v/cm
From equation 2
Un = -μE.
Un = - 1350cm^2/vs × 5000
= -6750000cm/s
From equation 3
Vp = μE
= 480cm^2/vs × 5000
= 2400000cm/s
Since it was stated in the question that we should contrast between hole drift and electron drift.
6750000/2400000
= 2.8125
Hence the electron drift velocity is 2.8 times that of hole drift velocity indicating that the speed of the electron through the silicon was faster.
The covers and guardrails are required in all of the following areas except ditches.
<h3>Do open pits require covers and guardrails?</h3>
Yes, they do need a covers and/or guardrails and it is one that is known or shall be provided to help in the protection of personnel from the hazards that pertains to open pits, tanks, vats and others.
Note that they are often needed that is covers and/or guardrails need to be provided to help to protect personnel.
Therefore, The covers and guardrails are required in all of the following areas except ditches.
Learn more about guardrails from
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Answer:
ΔU =195 KJ
W=0 KJ
Explanation:
Given that
Mass of air m=3 kg
heat absorb by air =195 KJ
Cv=0.741 KJ/kgK
If we assume that air is as ideal gas so
Given that container is rigid it means that volume of system is constant so W=0
From first law of thermodynamics
Q=ΔU + W
⇒Q= ΔU (W=0)
So ΔU =195 KJ
And work done will be zero because because it is a constant volume process.
Answer:
I am not noobqueen of the square footage
Explanation:
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