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ExtremeBDS [4]
1 year ago
10

Sodium chloride is composed of molecules that are stable when dry. In water, the atoms of the molecules separate from each other

. What type of chemical bond holds the dry substance together
Chemistry
1 answer:
astra-53 [7]1 year ago
3 0

The molecules of Sodium chloride holds a chemical bond to become stable when dry is an ionic bond.

<h3>What are chemical bonds?</h3>

The chemical bonds are those which holds the atoms of molecules together and creates a temporary connection between them.

The three major types of chemical bonds are:

  • Ionic bonds
  • Covalent bonds
  • Metallic bonds

<h3>What are ionic bonds?</h3>

The ionic bonds generally occurs in between a metal and a nonmetal ions.

The atoms share electrons in between them to become stable, forms ions. Due to electric attraction between these ions forms a bond between them. That bond is called as Ionic bond.

<h3>The type of chemical bond in Sodium chloride:</h3>

Sodium chloride - NaCl

Where Na(sodium) forms Na⁺ ion(metal) by sharing electrons with the chlorine atom and Cl(chlorine) forms Cl⁻ ion(non-metal).

So, due to the attraction between the anion and the cation, a bond is established between them. So, it is called Ionic bond.

Therefore, the chemical bond in Sodium chloride is an Ionic bond.

Learn more about chemical bonds here:

brainly.com/question/704297

#SPJ4

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A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

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Explanation:

Since he was able to drag the keys along the table by moving the magnet, it shows that magnetic forces acts a distance.

Magnetism is a property exhibited by a wide range of materials.

Around a bar magnet, there are field forces in which the forces of the magnets are felt.

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  • This is why magnetic forces act at a distance.

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Electromagnet brainly.com/question/2191993

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From the above reaction, we see clearly that Al displaces H from HCl. This is clearly a single displacement reaction.

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