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3 years ago

If more solvent is added to a solution:

Chemistry

1 answer:

Nadusha1986 [10]3 years ago

5 0

Answer:

The answer would be A

Explanation:

If more solvent is added, the solution becomes unsaturated because in principle it is capable of dissolving more solute.

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When a certain amount of MgF2 is added to water, the freezing point lowers by 3.5° C. What was the molality of the

Leni [432]

The molality of the solution is obtained as 0.63 m.

<h3>What is the freezing point?</h3>

The freezing point is the temperature at which the liquid is converted into solid.

We know that;

ΔT = 3.5° C

K = 1.86° C/m

i = 3

m = ?

Thus;

ΔT = K m i

m = ΔT/K i

m = 3.5° C/ 1.86° C/m * 3

m = 0.63 m

Learn more about freezing point:brainly.com/question/3121416

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6 0

2 years ago

What's the oxidation number of Li in LiNO3

Studentka2010 [4]

Explanation:

To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.

The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit

The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.

The algebraic sum of all oxidation number of atoms in a neutral compound is zero;

The radical NO₃ has a formal charge of -1;

let the oxidation number of Li = x

x + (-1) = 0

x = + 1

learn more:

Oxidation number brainly.com/question/10017129

#learnwithBrainly

4 0

3 years ago

How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

zhenek [66]

Answer:

Grams of mercury= 0.06 g of Hg

Note: The question is incomplete. The complete question is as follows:

A compact fluorescent light bulb contains 4 mg of mercury. How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

Explanation:

Since one fluorescent light bulb contains 4 mg of mercury,

15 such bulbs will contain 15 * 4 mg of mercury = 60 mg

1 mg = 0.001 g

Therefore, 60 mg = 0.001 g * 60 = 0.06 g of mercury.

Compact fluorescent lightbulbs (CFLs) are tubes containing mercury and noble gases. When electricity is passed through the bulb, electron-streams flow from a tungsten-coated coil. They collide with mercury atoms, exciting their electrons and creating flashes of ultraviolet light. A phosphor coating on the inside of the tube absorbs this UV light flashes and re-emits it as visible light. The amount of mercury in a fluorescent lamp varies from 3 to 46 mg, depending on lamp size and age.

5 0

3 years ago

PLEASEEE HELPPPP I WILL AWARD BRAINLIEST

vampirchik [111]

Yesssirrrrrrrrr someone answer

3 0

3 years ago

For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this

Salsk061 [2.6K]

The following are the steps to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3 N = +5

O = -2 O = -2

Ag = +1 Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

NO2– -----> NO3–

Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

NO2– + H2O -----> NO3–

Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

NO2– + H2O -----> NO3– + 2H+

Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

NO2– + H2O -----> NO3– + 2H+ + 2e-

Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

NO2– + H2O -----> NO3– + 2H+ + 2e-

2 Ag+ + 2e------> 2 Ag(s)

3 0

3 years ago