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asambeis [7]
2 years ago
12

If more solvent is added to a solution:

Chemistry
1 answer:
Nadusha1986 [10]2 years ago
5 0

Answer:

The answer would be A

Explanation:

If more solvent is added, the solution becomes unsaturated because in principle it is capable of dissolving more solute.

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PLEASE HELP
Rudik [331]

Answer

solids conduct heat more efficiently ! basically their particles are more tightly packed and stay in that position, so the heat transfer by collision allows for the best conduction

Explanation:

hope this helps ! :)

7 0
3 years ago
What does homogeneous and herogeneous mean?
serious [3.7K]
Homogeneous:

denoting a process involving substances in the same phase (solid, liquid, or gaseous).

Herogeneous:

of or denoting a process involving substances in different phases (solid, liquid, or gaseous).




7 0
3 years ago
Which item does not depend on rare earth elements?
Alisiya [41]

Answer:

Perrous magnets

Explanation:

6 0
2 years ago
oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene
Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{M_{NH_3}}{M_{H_2S}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=0.71

Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

5 0
3 years ago
Read 2 more answers
Write a mechanism for the esterification of propanoic acid with 18O-labeled ethanol. Show clearly the fate of the 18O label. (b)
tatuchka [14]

Answer:

See explanation and images attached

Explanation:

a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.

b)  In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.

5 0
3 years ago
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