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Alenkasestr [34]
3 years ago
12

Suppose you used 2.613 g of THAM to make the 250 mL THAM solution and it took 38.58 mL of your unknown HCl solution to reach the

end point of the titration. What is the molarity of the HCl solution?
Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer:

good question

Explanation:

hm good theory. how r u

Hello, eve This is the LONGEST TEXT EVER! I was inspired by the various other "longest texts ever" on the internet, and I wanted to make my own. So here it is! This is going to be a WORLD RECORD! This is actually my third attempt at doing this. The first time, I didn't save it. The second time, the Neocities editor crashed. Now I'm writing this in Notepad, then copying it into the Neocities editor instead of typing it directly in the Neocities editor to avoid crashing. It sucks that my past two attempts are gone now. Those actually got pretty long. Not the longest, but still pretty long. I hope this one won't a

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How does a generator transform mechanical energy into electrical energy?
RSB [31]

Answer:

C.) A generator transforms mechanical energy into electrical energy with the help of static electricuty

Example:

they convert mechanical or chemical energy into electrical energy. They do this by capturing the power of motion and turning it into electrical energy by forcing electrons from the external source through an electrical circuit.

(Hope this helps) sorry if it's wrong

5 0
3 years ago
How many grams of CO are needed to react with an excess of Fe 2 O 3 to produce 209.7 g Fe?
gavmur [86]

Answer:

Mass = 157.5 g

Explanation:

Given data:

Mass of CO needed  = ?

Mass of Fe formed = 209.7 g

Solution:

Chemical equation:

3CO + F₂O₃   →       2Fe + 3CO₂

Number of moles of Fe:

Number of moles = mass/ molar mass

Number of moles = 209.7 g/ 55.85 g/mol

Number of moles = 3.75 mol

Now we will compare the moles of iron and carbon monoxide.

                               Fe            :              CO

                                 2            :              3

                                3.75         ;             3/2×3.75 = 5.625 mol

Mass of CO:

Mass = number of moles × molar mass

Mass = 5.625 mol × 28 g/mol

Mass = 157.5 g

4 0
2 years ago
Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:
dem82 [27]

Answer:

The percent yield of the reaction is 62.05 %

Explanation:

Step 1: Data given

Volume of methane = 25.5 L

Pressure of methane = 732 torr

Temperature = 25.0 °C = 298 K

Volume of water vapor = 22.0 L

Pressure of H2O = 704 torr

Temperature = 125 °C

The reaction produces 26.0 L of hydrogen gas measured at STP

Step 2: The balanced equation

CH4(g) + H2O(g) → CO(g) + 3H2(g)

Step 3: Calculate moles methane

p*V = n*R*T

⇒with p = the pressure of methane = 0.963158 atm

⇒with V = the volume of methane = 25.5 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 298 K

n = (p*V) / (R*T)

n = (0.963158 * 25.5 ) / ( 0.08206 * 298)

n = 1.0044 moles

Step 4: Calculate moles H2O

p*V = n*R*T

⇒with p = the pressure of methane = 0.926316 atm

⇒with V = the volume of methane = 22.0 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 398 K

n = (p*V) / (R*T)

n = (0.926316 * 22.0) / (0.08206 * 398)

n = 0.624 moles

Step 5: Calculate the limiting reactant

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

H2O is the limiting reactant. It will completely be consumed (0.624 moles).

Methane is in excess. There will react 0.624 moles. There will remain 1.0044 - 0.624 moles = 0.3804 moles methane

Step 6: Calculate moles hydrogen gas

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

For 0.624 moles H2O we'll have 3*0.624 = 1.872 moles

Step 9: Calculate volume of H2 at STP

1.0 mol at STP has a volume of 22.4 L

1.872 moles has a volume of 1.872 * 22.4 = 41.9 L

Step 10: Calculate the percent yield of the reaction

% yield = (actual yield / theoretical yield) * 100 %

% yield = ( 26.0 L / 41.9 L) *100 %

% yield = 62.05 %

The percent yield of the reaction is 62.05 %

6 0
2 years ago
Read 2 more answers
2H2S + 3O2 → 2SO2 + 2H2O<br><br><br>1. For every 10.0 g of H2S how many moles of SO2 are formed?
Veseljchak [2.6K]

Answer:10

Explanation:

7 0
2 years ago
Necesito la respuesta
aleksandrvk [35]

Answer:

la tercera caja (3rd box)

Explanation:

usa desmos para obtener más ayuda

4 0
2 years ago
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