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Alenkasestr [34]
3 years ago
12

Suppose you used 2.613 g of THAM to make the 250 mL THAM solution and it took 38.58 mL of your unknown HCl solution to reach the

end point of the titration. What is the molarity of the HCl solution?
Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer:

good question

Explanation:

hm good theory. how r u

Hello, eve This is the LONGEST TEXT EVER! I was inspired by the various other "longest texts ever" on the internet, and I wanted to make my own. So here it is! This is going to be a WORLD RECORD! This is actually my third attempt at doing this. The first time, I didn't save it. The second time, the Neocities editor crashed. Now I'm writing this in Notepad, then copying it into the Neocities editor instead of typing it directly in the Neocities editor to avoid crashing. It sucks that my past two attempts are gone now. Those actually got pretty long. Not the longest, but still pretty long. I hope this one won't a

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How many moles of H 2 can be formed if a 3.24 g sample of M g reacts with excess H C l ?
Ganezh [65]

Answer:

0.135 mole of H2.

Explanation:

We'll begin by calculating the number of mole in 3.24 g of Mg. This can be obtained as follow:

Mass of Mg = 3.24 g

Molar mass of Mg = 24 g/mol

Mole of Mg =?

Mole = mass /Molar mass

Mole of Mg = 3.24/24

Mole of Mg = 0.135 mole

Next, we shall write the balanced equation for the reaction. This is illustrated below:

Mg + 2HCl —> MgCl2 + H2

From the balanced equation above,

1 mole of Mg reacted to produce 1 mole of H2.

Finally, we shall determine the number of mole of H2 produced by reacting 3.24 g (i.e 0.135 mole) of Mg. This can be obtained as follow:

From the balanced equation above,

1 mole of Mg reacted to produce 1 mole of H2.

Therefore, 0.135 mole of Mg will also react to produce 0.135 mole of H2.

Thus, 0.135 mole of H2 can be obtained from the reaction.

3 0
3 years ago
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