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4 years ago

you rent a car in Germany with a gas mileage rating of 12.8km/L. What is its rating in miles per gallon?

Chemistry

2 answers:

Ivanshal [37]4 years ago

8 0

Answer: The mileage rating of the car is 30.05 miles per gallon

Explanation:

We are given:

Mileage rating = 12.8 km/L

To convert this level into milligrams per deciliters, we use the conversion factor:

1 mile = 1.61 km

1 gallon = 3.78 L

Converting the above rating into miles per gallon, we get:

$\Rightarrow (\frac{12.8km}{L})\times (\frac{1mile}{1.61km})\times (\frac{3.78L}{1 gallon})\\\\\Rightarrow 30.05miles/gallon$

Hence, the mileage rating of the car is 30.05 miles per gallon

Oksi-84 [34.3K]4 years ago

4 0

so one liter is about 2. something gallons so at 12.8 km/l you would get about 30 mpg which is insane but yeah

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Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

Answer: The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

Explanation:

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

4 0

3 years ago

How many grams of co2 is produced when oxygen reacts with carbon?

Serggg [28]

44g of CO2 can produce by the reaction of carbon with oxygen

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4 years ago

What is the average mass of a single chlorine atom in grams

Archy [21]

If you look at the chlorine box, with the symbol Cl, you see the atomic mass is equal to 35.453 atomic mass units. This is the weighted average mass of chlorine, including its isotopes, as found in nature. This also means that one mole of chlorine atoms has a mass of 35.453 grams.

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3 years ago

The molar mass of hydrogen molecules is 2g/mol and the molar mass of oxygen molecules is 32g/mol. What is the ratio of the avera

Alona [7]

Answer:

Explanation:

For an ideal gas, the average kinetic energy is given by:

Ek = (3/2)*n*R*T

Where n is the number of moles, R is the gas constant (8.31 J/mol*K), and T the temperature. The gases have the same number of moles, and the same temperature, so they will have the same average kinetic energy:

Ek = (3/2)*1*8.31*300

Ek =3739.5 J

So, the ratio between then is 1.

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4 years ago

Which sample of matter is classified as a substance? (1) air (3) milk(2) ammonia (4) seawater

jeyben [28]

A chemical substance has the characteristics that it cannot be separated by physical methods. Seawater and milk can be separated by sedimentation, and air has different components depending on other aspects (such as elevation). Only ammonia is a substance. (thus it can have a formula: NH3)

3 0

3 years ago