Answer:
1.024 x 10⁻²²g
Explanation:
Data Given:
mass of copper = 63.5 g
no. of atoms of copper = 6.02 x10²³ atoms
mass of of an average copper = ?
Solution:
As 6.02 x10²³ atoms have 63.5 g of mass then what will be the mass of atom.
Apply unity formula
63.5 g of copper ≅ 6.02 x10²³ atoms of copper
mass of copper atom ≅ 1 atom of copper
Do cross multiplication
mass of copper atom = 1 atom x 63.5 g / 6.02 x10²³ atoms
mass of copper atom = 1.024 x 10⁻²² g
mass of an average copper atom = 1.024 x 10⁻²² g
It’s hard which class are u
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles
moles of O2 is half
so 40.04 x 0.5
20.02moles
grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g
Answer:
to find the number of electrons you need the charge of the element.
Answer:
It Is Considered The "negative" Electrode
Explanation:
An electrochemical cell is an electrolytic cell that drives a non-spontaneous redox reaction through the application of electrical energy. This cell is used to decompose chemical compounds, in a process called electrolysis. An electrode at which reduction take place is called the cathode. In reduction, electrons travel toward the site of reduction such that the negative charge is on the cathode.
