Answer:
see explanation below
Explanation:
In this case, we have the following reaction:
Mg + 1/2O₂ -------> MgO
Now, according to this reaction we want to know the percent composition of MgO. The problem is not providing the mass of the initial reactants and the product, so we can use the atomic weights of the components, to do this
The molecular weight of Mg is 24.305 g/mol, and O is 15.999 g/mol, so, let's calculate the molar mass of MgO:
MM MgO = 24.305 + 15.999 = 40.304 g/mol
Now with this weight, let's see the percent composition of this compound:
%Mg = 24.305 / 40.304 * 100 = 60.304 %
%O = 15.999 / 40.304 * 100 = 39.696 %
And this would be the percent composition of MgO
Answer:A 1,2-dibromoheptene
Explanation:
What you were given is the balanced chemical equation
The total mass of the products is 10.76 g + 204.44 g = 215.20 g.
The masses of all the reactants but one are known so,
215.20 g - 120.00 g - 8.15 g - 75.00 g = 12.05 g
12.05 g is the mass of the unweighed barium nitrate.
