Answer:
Its potential energy decreases and itselectricpotential increases.
Explanation:
The electric potential does not depend on the charge but only on the magnitude of the electric field. In particular:
- Electric potential decreases when moving in the same direction of the electric field lines
- Electric potential increases when moving in the opposite direction to the field lines
So in this case, since the electron is moving in a direction opposite to the field, the electric potential increases.
However, the electric potential energy of a charge is given by
where
q is the charge
V is the electric potential
Here we said that the electric potential is increasing: however, the charge q of an electron is negative. This means that the product (qV) is increasing in magnitude but it is negative, so the potential energy of the electron is decreasing.
A motion security line is a system that is used to detect motion.
The input for the system is MOTION and the output is LIGHT. That is, when the system detects motion it switch on light.
Remember, an Input is the information that was inserted into a system while the output is the result of the processed information.
Answer:
<em><u>F1 </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em><em><u> </u></em><em><u>N </u></em><em><u>and </u></em><em><u>F2 </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>4</u></em><em><u> </u></em><em><u>N</u></em>
Explanation:
<em>Formula </em><em>used </em><em>=</em><em>></em><em> </em><em> </em><em>F </em><em>=</em><em> </em><em>m×</em><em>a</em><em> </em><em>and </em><em>v-u=</em><em> </em><em>at</em>
So, as we know force = mass × acc.
so acc. of first block = <math> F1/5 </math>. and acc. of second block = <math> F2/ 8 </math>.......... so as v-u= at.. now
Here u= 0 as the objects are placed at rest initially..
thus, v= at
<em>FOR </em><em>1</em><em>S</em><em>T</em><em> </em><em>BLOCK</em>
16= <math> F1/5 </math> × 5 ==> <em><u>F1 </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em><em><u> </u></em><em><u>N</u></em>
<em>FOR </em><em>2</em><em>N</em><em>D</em><em> </em><em>BLOCK</em>
15= <math> F2/ 8 </math> × 5 ==> <em><u>F2=</u></em><em><u> </u></em><em><u>2</u></em><em><u>4</u></em><em><u> </u></em><em><u>N</u></em>
Answer:
a) Magnitude of the average velocity from t = 0 to t = 2 s = 2.24 m/s
b) Magnitude of the average velocity from t = 0 to t = 5 s = 3.16 m/s
Explanation:
a) Velocity is rate of change of position.
A particle's position coordinates (x, y) are (1.0 m, 3.0 m) at t = 0
A particle's position coordinates (x, y) are (5.0 m, 5.0 m) at t = 2.0 s
Displacement = (5-1)i + (5-3)j = 4i + 2j
Change in time = 2s
Velocity
Magnitude of velocity
b) Velocity is rate of change of position.
A particle's position coordinates (x, y) are (1.0 m, 3.0 m) at t = 0
A particle's position coordinates (x, y) are (14.0 m, 12.0 m) at t = 5.0 s
Displacement = (14-1)i + (12-3)j = 13i + 9j
Change in time = 5s
Velocity
Magnitude of velocity