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oksano4ka [1.4K]
2 years ago
12

Considera que las masas de los cuerpos son m1 y m2, y sus velocidades antes del choque v1 y v2. Utiliza la ley de conservación d

e la cantidad de movimiento para obtener la fórmula que permite predecir la velocidad común v de los cuerpos después del choque.
Physics
1 answer:
Tems11 [23]2 years ago
7 0

Answer:

v = (m1*v1 + m2*v2)/(m1 + m2)

Explanation:

Sabemos que para un objeto de masa m y velocidad v, podemos escribir al momento lineal como:

P = m*v

Entonces, si inicialmente tenemos dos cuerpos con masas m1 y m2, con respectivas velocidades v1 y v2, el momento inicial de cada cuerpo será:

P1 = m1*v1

P2 = m2*v2

Luego estos objetos chocan y comienzan a moverse juntos (lo podemos pensar como un solo cuerpo de masa m1 + m2) con una velocidad común v, entonces el momento final será:

P' = (m1 + m2)*v

La ley de conservación de momento nos dice que el momento total de un sistema debe conservarse.  

Entonces el momento total del sistema al inicio:

P = P1 + P2 = m1*v1 + m2*v2

Debe ser igual al momento final del sistema:

P' =  (m1 + m2)*v

entonces tenemos la ecuación:

m1*v1 + m2*v2 = (m1 + m2)*v

Resolviendo esto para v, obtenemos:

v = (m1*v1 + m2*v2)/(m1 + m2)

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The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 m
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Answer:

The focal length of eyepiece is 3.68 cm.

Explanation:

Given that,

Distance = 19 cm

Focal length = 5.5 mm

Magnification = 200

Object distance = -25 cm

We need to calculate the focal length

Using formula of magnification

m=\dfrac{d}{f_{o}}+\dfrac{-25}{f_{0}f_{e}}

Put the value into the formula

f_{e}=\dfrac{19\times(-25)}{.55(-200-\dfrac{19}{.55})}

f_{e}=3.68\ cm

Hence, The focal length of eyepiece is 3.68 cm.

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A college student is working on her physics homework in her dorm room. Her room contains a total of 6.0 x 10^26 gas molecules. A
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Answer:

Temperature, T = 3.62 kelvin

Explanation:

It is given that,

Total number of gas molecules, N=6\times 10^{26}

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Energy of a gas molecules is given by :

\Delta E =\dfrac{3}{2}NkT

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T=\dfrac{2\times P\times t}{3Nk}

T=\dfrac{2\times 125\times 360}{3\times 6\times 10^{26}\times 1.38\times 10^{-23}}

T = 3.62 K

So, the temperature increases by 3.62 kelvin. Hence, this is the required solution.

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Answer:

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