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Inga [223]
3 years ago
15

The distance of Saturn from the sun is: < 1 A.U. > 1 A.U. = 1 A.U.

Physics
2 answers:
sertanlavr [38]3 years ago
6 0

Answer:

1 astronomical unit is the average distance from the Earth to the Sun; approximately 150 million km. At its closest point, Saturn is 9 AU, and then at its most distant point, it's 10.1 AU. Saturn's average distance from the Sun is 9.6 AU. We have written many articles about Saturn for Universe Today.

Explanation:

Hatshy [7]3 years ago
3 0
Please mark the first girl as brainest she tried her best
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How does newtons law of the universal gravitation help scientist describe the universe
Afina-wow [57]
You need to know everything is made of atoms they are always colliding and they are never still because you'd think that every thing in space is still all the time even if it's not making visibly
5 0
3 years ago
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A stone is dropped at t = 0. A second stone, with twice the mass of the first, is dropped from the same point at t = 181 ms. How
lara [203]

Answer:

the center of mass is 316,670m bellow the release point.

Explanation:

First, we must find the distance at which the objects are in time t = 360s

We will use the formula for vertical distance in free fall

h=v_{0}t+\frac{1}{2} gt^2

v_{0} is the initial velocity, is 0 for both stones since they were just dropped.

g is acceleration of gravity and t is time (g=9.81m/s^2)

At t=360s the first stone has been falling for the entire 360 seconds, its position h1 is:

h_{1}=\frac{1}{2} (9.82m/s^2)(360s^2)=635,688m

And at 360 seconds the second stone has been fallin fort= 360s -181 s = 179s, so its position h2 is:

h_{2}=\frac{1}{2} (9.81m/s^2)(179)^2=157,161.1m

And finally using the equation for the center of mass:

CM=\frac{m_{1}h_{1}+m_{2}h_{2}}{m_{1}+m_{2}}

We know that the mass of the second stone is twice the mass of the first stone so:

m_{1}=m\\m_{2}=2m

replacing these values in the equation for the center of mass

CM=\frac{mh_{1}+2mh_{2}}{m+2m}

CM=\frac{m(h_{1}+2h_{2})}{3m}=\frac{h_{1}+2h_{2}}{3}

Finally, replacing the values we found fot h1 and h2:

CM=\frac{635,688m+2(157,161.1m)}{3}=316,670m

the center of mass is 316,670m bellow the release point.

8 0
4 years ago
Ashen light (or earthshine) is
Annette [7]

Answer:

E

Explanation:

The condition known as Earth shine takes place when the reflecting sunlight from our world illuminates the Moon's dark side. This is usually the result that the dark side of the moon is showered in a dim, faint light. It is also called  as the ashen light of the Moon, or in the wings of the new Moon as the old Moon.

Therefore the correct reason would be e. sunlight reflected by Earth that illuminates the "dark" portion of the Moon.

8 0
3 years ago
Help me pleaseeee I will give you 42 points!<br> (I am dumb so that’s why)
Anit [1.1K]
Search each one of them up on GOOGLE it’s easier trust me
7 0
4 years ago
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A 5.00 kilogram block slides along a horizontal,frictionless surface at 10.0 meters per second. for 4.00 seconds. The magnitude
finlep [7]
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
                   = (5 * 10) Kg m/s
                   = 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
5 0
3 years ago
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