How far does a roller coaster travel if it accelerates at 2.83 m/s2 from an initial

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is

Bumek [7]

Answer:

Answer is 25 kg m/s.

Explanation:

Given Data ;

mass = 0.5 kg

velocity = 10 m/s

Find ;

K.E = ?

Formula ;

KE = 1/2 mv 2

Solution:

KE = 1/2(0.5)(10)²(kg)(m/s)

=25 kg m/s

7 0

3 years ago

An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons

Nady [450]

To solve this problem it is necessary to apply the concepts related to the conservation of energy, specifically the potential elastic energy against the kinetic energy of the body.

By definition this could be described as

$PE = KE$

$\frac{1}{2}kx^2 = \frac{1}{2}mv^2$

Where

k = Spring constant

x = Displacement

m = mass

v = Velocity

This point is basically telling us that all the energy in charge of compressing the spring is transformed into the energy that allows the 'impulse' seen in terms of body speed.

If we rearrange the equation to find v we have

$v = \sqrt{\frac{kx^2}{m}}$

Our values are given as

$m = 1000kg$

$k = 5.75*10^6N/m$

$x = 3.12*10^{-2}m$

Replacing at our equation we have then,

$v = \sqrt{\frac{kx^2}{m}}$

$v = \sqrt{\frac{(5.75*10^6)(3.12*10^{-2})^2}{1000}}$

$v = 2.3658m/s$

Therefore he speed of the car before impact, assuming no energy is lost in the collision with the wall is 2.37m/s

4 0

3 years ago

In a mass spectrometer, a compound is first vaporized and converted into ions, which are then separated based on a difference in

Crazy boy [7]

The correct answer is their difference in the charge to mass ratio a mass spectrometer, a compound is first vaporized and converted into ions .

Mass spectrometry is a technique for determining the mass-to-charge ratio (m/z) of one or more molecules in a sample. These measurements are frequently used to calculate the precise molecular weight of the sample components.

The speed at which positively charged ions move through a vacuum chamber toward a negatively charged plate is measured by mass spectrometers. ToF, magnetic sector, and quadrupole mass spectrometers are all commonly used in SIMS instrumentation.The MS/MS has three major advantages: the ability to study numerous molecules regardless of whether they are from the same structural family or not; the ability to highlight the specific metabolites of a disease; and it is an automated technique that allows for large-scale analysis.

Learn more about Mass spectrometry here :-

brainly.com/question/5020187

#SPJ4

8 0

2 years ago

Suppose you start an antique car by exerting a force of 270 N on its crank for 0.275 s. What angular momentum is given to the en

Ksenya-84 [330]

Answer:

$L_f=22.27\ kg-m^2/s$

Explanation:

Given that,

Force exerted on an antique car, F = 270 N

Time, t = 0.275 s

Distance, d = 0.3 m

To find:

The angular momentum given to the engine.

Solution,

We know that the relation between the angular momentum and the torque is given by :

$\tau=\dfrac{dL}{dt}$

Since, $\tau=d\times F$

$dF=\dfrac{dL}{dt}$

$d.F=\dfrac{L_f-L_i}{t}$

$d.F=\dfrac{L_f}{t}$

$L_f=d\times F\times t$

$L_f=0.3\ m\times 270\ N\times 0.275\ s$

$L_f=22.27\ kg-m^2/s$

So, the angular momentum given to the engine is $22.27\ kg-m^2/s$ .

7 0

4 years ago

An AC circuit has an RMS voltage of 80 VAC. What's the circuit's average voltage?

yaroslaw [1]

-- The RMS value of an AC waveform is (1/2)(√2) x (peak value)

So the peak value is (√2) x (RMS value)

-- The Average value of an AC waveform is (2/π) x (peak value)

So the peak value is (π/2) x (Average value).

-- So far, this is all very entertaining, but how does it help us answer the question.

Well, we found the peak value in terms of the RMS and in terms of the Average. So we can set these equal to each other, and solve for the Average in terms of the RMS. This sounds like such a good plan, I think I'll do it !

Peak = (√2) x (RMS value) and Peak also = (π/2) x (Average value).

So (√2) · RMS = (π/2) · Average .

Divide each side by π : (√2) · RMS / π = (1/2) · Average

Multiply each side by 2 : Average = (2/π) · (√2) · RMS .

You said that the RMS value is 80 V, so

Average = (2/π) · (√2) · (80)

Average = (2 · √2 / π) · (80)

Average = 160√2 / π

Average = 72 volts . (But be sure to read the 'gotcha' below.)

Now I'll go ahead and tell you the 'gotcha':

All of these numbers are true, as far as they go. But the 'average' is only true for 1/2 cycle of an AC wave. Picture an AC wave in your mind. You'll see that it spends just as much time being negative as it spends being positive. So the 'average' of any number of AC whole cycles is zero.

7 0

3 years ago