We know that the acceleration due to gravity g is: g =
9.81 m/s^2
So the centripetal acceleration (w) is:
w^2 = 1.5 g / r
w^2 = 1.5 * (9.81 m/s^2) / 5 m
w = 1.716 rad / s
To convert to rad to rev:
w = (1.716 rad / s) * (1 rev / 2π rad) * (60 s/min)
<span>w = 16.4 rev/min </span>
Waning Gibbous would be the phase?
Answer:
The focal length of eye piece is 6.52 cm.
Explanation:
Given that,
Angular Magnification of the microscope M = -46
the distance between the lens in microscope L= 16 cm
The focal length of objective f₀ = 1.5 cm
Normal near point N = 25 cm
Have to find focal length of eye piece f ₙ =?
The angular magnification is given by
M ≈ - (L-fₙ)N/f₀fₙ
Rearranging for fₙ
fₙ =L(1 - Mf₀/N)⁺¹
=18/2.76
fₙ = 6.52 cm
The focal length of eye piece is 6.52 cm.
Answer:
Explanation:
According to question,
Charge 1 and charge 2 are 
The distance between charges is 2 m
We need to find the force with which two positive charges repel. It is called electrostatic force of repulsion. It can be given by :
So, the electric force of repulsion is 
.
