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ahrayia [7]
3 years ago
11

Based on the information presented in the graph, what is the velocity of the object?

Physics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

3 m/s

Explanation:

<u>The velocity of a position-time graph is the slope of the line.</u>  Slope is rise over run, or rise divided by run.  The rise (how many units the line goes up) is 3 units and the run is 1 unit.  3/1 is 3, so the velocity is 3 m/s.

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6.67x10^-11x60x5.98x10^24
Maurinko [17]
2.393196e+16 hope this helps
8 0
3 years ago
Can someone help me?
Cloud [144]

What do we know that might help here ?

-- Temperature of a gas is actually the average kinetic energy of its molecules.

-- When something moves faster, its kinetic energy increases.

Knowing just these little factoids, we realize that as a gas gets hotter, the average speed of its molecules increases.

That's exactly what Graph #1 shows.

How about the other graphs ?

-- Graph #3 says that as the temperature goes up, the molecules' speed DEcreases.  That can't be right.

-- Graph #4 says that as the temperature goes up, the molecules' speed doesn't change at all.  That can't be right.

-- Graph #2 says that after the gas reaches some temperature and you heat it hotter than that, the speed of the molecules starts going DOWN.  That can't be right.  

--

4 0
3 years ago
A mouse is walking at 2.45 m/s. He sees a cat and accelerates at 4.92 m/s/s. How much time does it take him to reach a speed of
alexandr1967 [171]
Speed= (4.92-2.45) 2.47 m/s
Distance= ?
You didn't mention about the distance?
5 0
3 years ago
You wish to place a spacecraft in a circular orbit around the earth so that its orbital speed will be 4.00×103m/s. What is this
Levart [38]

Answer:

The radius of orbit=2.49\times 10^7 m

Explanation:

We are given that

Orbital speed=4.00\times 10^3m/s

We have to find the radius of orbit of spacecraft.

We know that

Gravitational constant=6.67\times 10^{-11}m^3/kgs^2

Mass of earth=5.972\times 10^{24} kg

Orbital speed=\sqrt{\frac{GM}{r}}

Where G= Gravitational constant

M=Mass of earth

r=Radius of orbit

Substitute the values in the formula

4\times 10^3=\sqrt{\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{r}

Squaring on both sides

16\times 10^6=\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{r}

r=\frac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{16\times 10^6}

r=2.49\times 10^7 m

Hence, the radius of orbit=2.49\times 10^7 m

7 0
4 years ago
A block slides down a frictionless plane having an inclination of 15.0°. The block starts from rest at the top, and the length o
nalin [4]

Answer: check the pic

Explanation:

8 0
3 years ago
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