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Dmitriy789 [7]
2 years ago
7

When using three letters to name an angle, the middle letter represents the ____.

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
3 0

Answer:

Vertex

Step-by-step explanation:

Vertex is the 'point' of an angle

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P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
50 points for whoever answers the right answer
Olin [163]

Answer:

128

Step-by-step explanation:

Supplementary means they sum to 180, and it's also a straight line. 180-49 = 131. 131-3 = 128, or x.

6 0
2 years ago
Read 2 more answers
What does the word Tangent mean ?​
marin [14]

Answer:

ur mom XD :/

Step-by-step explanation:

8 0
2 years ago
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W is greater than -1 and less than or equal to 4<br> Use a only once in your inequality.
Mice21 [21]

Answer:

-1 + w ≤ 4

Step-by-step explanation:

w is greater than -1 = -1 + w

Less than or equal to 4 = (anything less than or equal to 4)≤4

7 0
3 years ago
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When comparing the functions using the equation, which conclusion can be made?
ankoles [38]

Answer:

  domain of f(x) is x ≤ 0; domain of f^-1(x) is x ≥ 4

Step-by-step explanation:

The square root function will always give a positive value, so the opposite of the square root function will give non-≤positive values. That means ...

  • the domain of f(x) is restricted to non-positive values
  • the domain of the inverse function is restricted to values of x that make the root be of a non-negative number: x ≥ 4

The domain of f(x) is x ≤ 0; the domain of f^-1(x) is x ≥ 4.

8 0
3 years ago
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