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rodikova [14]
1 year ago
8

Solve this whole experiment,

Chemistry
1 answer:
pav-90 [236]1 year ago
7 0
Are you saying yes or no to this Bec it’s your prediction
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Consider the atom with the chemical symbol Ru.
babymother [125]

Answer:

96.

Explanation:

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2 years ago
Which elements are considered metals? Non-metals? Metalloids?
kolbaska11 [484]

The answer is in the photo.

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2 years ago
What molecule(s) could diffuse across the plasma membrane? question 31 options: disaccharides fe2 tryptophan amino acid ch4
nevsk [136]

The molecule that could diffuse across the plasma membrane is methane (CH4).

<h3>What is diffusion?</h3>

Diffusion is the movement of fluids or substances from regions of high concentration toward regions of lower concentration.

The plasma membrane is the semipermeable membrane that surrounds the cytoplasm of a cell. The semipermeability means that it allows some molecules through but blocks other substances.

The semipermeable plasma membrane readily allows the passage of small hydrophobic and polar molecules.

Therefore, the molecule that could diffuse across the plasma membrane is methane (CH4).

Learn more about semipermeability at: brainly.com/question/1652796

#SPJ1

7 0
1 year ago
Sulfur burns in the air to form 33.6L of sulfur dioxide. (S = 32, O =16, 64g of sulfur dioxide has 22.4L, 32g of oxygen has 22.4
ivolga24 [154]

The mass of oxygen reacted/required in this reaction is obtained as 48g.

<h3>What is stoichiometry?</h3>

The term stoichiometry has to do with mass- volume or mass - mole relationship which ultimately depends on the balanced reaction equation.

Now, we have the reaction; S + O2 ------>SO2

If 1 mole of sulfur dioxide contains 22.4 L

x moles of sulfur dioxide contains 33.6L

x = 1.5 moles of sulfur dioxide.

Since the reaction is 1:1, the number if moles of oxygen required/reacted is 1.5 moles.

Mass of oxygen required/reacted = 1.5 moles * 32 g/mol = 48g

Learn more anout stoichiometry: brainly.com/question/9743981

8 0
2 years ago
The rate of a certain reaction is given by the following rate law: rate Use this information to answer the question below. At a
AleksAgata [21]

Answer:

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

Explanation:

N_2+3H_2\rightarrow 2NH_3

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Initial rate of the reaction = R = 4.0\times 10^5 M/s

R = k\times [N_2][H_2]^3

4.0\times 10^5 M/s=k\times [N_2][H_2]^3

The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

[H_2]'=2[H_2]

R'=k\times [N_2][H_2]'^3=k\times [N_2][2H_2]^3

R'=8\times k\times [N_2][H_2]^3

R'=8\times R=8\times 4\times 10^5 M/s=3.2\times 10^6 M/s

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

7 0
3 years ago
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