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2 years ago

_____ occurs when the product of the ion concentrations exceeds the Ksp.

Chemistry

2 answers:

arlik [135]2 years ago

4 0

Precipitation occurs when the product of the ion concentration exceeds the Ksp.

serious [3.7K]2 years ago

4 0

Answer : Precipitation occurs when the product of the ion concentrations exceeds the $K__{sp}$ .

Explanation :

Ionic product : It is the product of the concentrations of the ions in solution raised to the same power by its stoichiometric coefficient in a solution of a salt. This takes place at any concentration. The ionic product is represented as, Q.

Solubility product constant : It is defined as the product of the concentration of the ions present in a solution raised to the power by its stoichiometric coefficient in a solution of a salt. This takes place at equilibrium only. The solubility product constant is represented as, $K__{sp}$ .

There are three cases for the solubility :

When $Q$ this means that the solution is unsaturated solution and more solid will be dissolve.
When $Q=k_{sp}$ this means that the solution is saturated solution.
When $Q>k_{sp}$ this means that the solution is supersaturated solution and solid will be precipitate.

Hence, the precipitation occurs when the product of the ion concentrations exceeds the $K__{sp}$ .

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Son las transformaciones que ocurren de un estado a otro de la materia, ocurren sin alterar la estructura molecular de la materi

Vladimir [108]

Los cambios de estado físico son transformaciones que ocurren de un estado de la materia a otro, sin cambiar la estructura molecular de la materia, es decir, sin transformarse en otras sustancias.

Los tres estados físicos básicos de la materia son:

sólido,
líquido y
gaseoso.

Se puede decir que son diferentes solo por la organización de sus partículas, lo que determina su cambio de estado pero sin cambiar la estructura molecular.

Cualquier sustancia se puede encontrar en estos tres estados físicos, dependiendo de su temperatura y presión.

El aumento de temperatura hace que las moléculas se separen y el aumento de presión hace que se acerquen.

En estado sólido las partículas están más juntas, en el líquido se mueven más y en el gas están bien separadas.

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brainly.com/question/17104364

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2 years ago

Manganese, Mn, forms two ions, one with a 2+ charge and one with a 3+ charge. What is the formula for manganese (II) sulfide?

maria [59]

It would be MnSO4

The (II) lets you know it’s the form with a 2+ charge and Sulfate has a 2- charge

These will cancel out making it plain MnSO4

If it was manganese (iii) sulfide the answer would be Mn2(SO4)3

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3 years ago

All of the following are true of carbohydrates except

Evgen [1.6K]

3. they make up larger compounds like fats and amino acids, would be the correct answer.

5 0

2 years ago

Read 2 more answers

Can someone please help me fill this out?

Mamont248 [21]

The states of matter is solid,liquid and gas & you go from there.

6 0

2 years ago

A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema

timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

V1= 5.76 L
T1= 22 °C= 295 °K (Being 0°C=273°K)
V2=17.28 L
T2=?

Replacing:

$\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}$

Solving:

$T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}$

T2= 885 °K = 612 °C

<u><em>The final temperature was 612 °C</em></u>

5 0

2 years ago