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aivan3 [116]
3 years ago
5

16.4 mL of 0.135 M NaOH is used to neutralize 46.9 mL of HCl. The concentration of the HCl solution is ____ M (3 decimal places)

.
Chemistry
1 answer:
marshall27 [118]3 years ago
5 0

The concentration of the HCl solution is 0.047 M.

Explanation:

Data given about acid and base:

volume of acid Vacid = 46.9 ml

molarity of acid =?

volume of the base (NaOH) = 16.4 ml

molarity of the base = 0.135 M

To know the concentration of the acid in this reaction, the formula used in titration  is used. It is

Macid X Vacid = Mbase X Vbase

the formula is rewritten as:

Macid = \frac{Mbase X Vbase}{Vacid}

putting the values in the equation:

Macid = \frac{0.135 X 16.4}{46.9}

          = 0.047 M

the concentration of the acid i.e HCl in the solution is of 0.047 M.

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A first order reaction has a rate constant of 0. 543 at 25°C. Given that the activation energy is 75. 9 kj/mol. Calculate the ra
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The rate constant of first order reaction at 32. 3 °C is 0.343 /s must be less the 0. 543 at 25°C.

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The specific rate steady is the proportionality consistent touching on the fee of the reaction to the concentrations of reactants. The fee law and the specific charge consistent for any chemical reaction should be determined experimentally. The cost of the charge steady is temperature established.

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