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Ivanshal [37]
2 years ago
8

How much more heat is transferred from the ocean to the atmosphere as latent heat rather than as sensible heat

Physics
1 answer:
kati45 [8]2 years ago
5 0

The amount of heat transferred from the ocean to the atmosphere as latent heat than sensible heat will be 10 times as much.

Latent heat and sensible heat are defined as follows:

  • Latent heat: It is the heat that leaves/enters a system during a process where the temperature of the system stays constant.
    Examples are phase changes where the latent heat from the system leaves (exothermic) or enters a system (endothermic).

  • Sensible heat: It is the heat that enters or exits a system when the temperature of the system is not constant. The entire heat flows through the two systems and in order to do so it requires a temperature difference between the systems.

Thus, the amount of heat transferred from the ocean to the atmosphere as latent heat than sensible heat will be 10 times as much.

Learn more about latent and sensible heat here:

<u>brainly.com/question/13499849</u>

#SPJ4

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Can a goalkeeper at his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance will
zmey [24]

The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

Explanation:

Consider the vertical motion of ball,

We have equation of motion v = u + at

     Initial velocity, u  = u sin θ

     Final velocity, v =  0 m/s    

     Acceleration = -g

     Substituting

                      v = u + at  

                      0 = u sin θ - g t

                      t=\frac{usin\theta }{g}

This is the time of flight.

Consider the horizontal motion of ball,

        Initial velocity, u =  u cos θ

        Acceleration, a =0 m/s²  

        Time, t=\frac{usin\theta }{g}  

     Substituting

                      s = ut + 0.5 at²

                      s=ucos\theta \times \frac{usin\theta }{g}+0.5\times 0\times (\frac{usin\theta }{g})^2\\\\s=\frac{u^2sin\theta cos\theta}{g}\\\\s=\frac{u^2sin2\theta}{2g}

This is the range.

In this problem

              u = 30 m/s

              g = 9.81 m/s²

              θ = 45° - For maximum range

Substituting

               s=\frac{30^2\times sin(2\times 45)}{2\times 9.81}=45.87m

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.

So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

6 0
4 years ago
A baseball accelerates downward at 9.8m/s. if the gravitational force acting on the baseball is 2.2n what is the baseballs mass
Neko [114]
hope this helps you.....

5 0
4 years ago
A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder?
AlekseyPX

Answer: 4m/s

Explanation:

8 0
3 years ago
A cyclist accelerates from a velocity of 10 miles/hour east until reaching a velocity of 20 miles/hour east in 5 seconds. What w
Sliva [168]

Answer:

a = 0.894\ m/s^2

Explanation:

<u>Motion with Constant Acceleration</u>

A body moves with constant acceleration when the speed changes uniformly in time. The equation used to find the final speed vf is

v_f=v_o+at

Where vo is the initial speed, a is the acceleration, and t is the time.

The cyclist has an initial speed of vo=10 miles/hour and ends up at vf=20 miles/hour in t=5 seconds.

Both speeds are given in miles/hour and we must convert it to m/s:

1 mile/hour = 0.44704 m/s

10 mile/hour = 4.47 m/s

20 mile/hour = 8.94 m/s

The acceleration is calculated by solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{8.94-4.47}{5}

a = 0.894\ m/s^2

3 0
3 years ago
What is the wavelength of an earthquake wave if it has a speed of 3 km/s and a frequency of 6 Hz?
disa [49]
Wavelength = c/f.
Wavelength =0.5km
8 0
3 years ago
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