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2 years ago

Which statement about velocity is true?

Physics

1 answer:

LekaFEV [45]2 years ago

8 0

Answer:

Velocity has both speed and direction. Speed is constant. ... Speed is measured over time.

Explanation:

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HELP ME PLEASE! according ohm's law if the resistance remains constant what would happen if you decrease the amount of voltage b

SpyIntel [72]

B.
technically it would depend if the resistors were in series or parallel but B is the answer.

7 0

2 years ago

HEY CAN YALL PLS HELP ME IN DIS!!!!!!!!!!!!!

Serga [27]

Answer:

Hey!!

Your answer is: 0.72

Explanation:

if 760=1 then...

550=x

=550÷760= 0.72 in two s.f

6 0

2 years ago

An ice skater accelerates backward for 5.0 second to final speed of 12m/s. If the acceleration backward was at a a rate of 1.5m/

Lisa [10]

Answer:

Initial velocity, U = 4.5m/s

Explanation:

Given the following data;

Final velocity, v = 12m/s

Time, t = 5 seconds

Acceleration, a = 1.5m/s²

To find the initial velocity, we would use the first equation of motion.

$V = U + at$

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

12 = U + 1.5*5

12 = U + 7.5

U = 12 - 7.5

Initial velocity, U = 4.5m/s

3 0

2 years ago

A truck is carrying a steel beam of length 13.0 m on a freeway. An accident causes the beam to be dumped off the truck and slide

PIT_PIT [208]

Answer:

$emf= 9.88 \times 10^{-3} T$

Explanation:

Given:

Length of the beam, $l=13\,m$

speed of the beam, $v=20\,m.s^{-1}$

magnitude of the vertical magnetic field, $B=38\times 10^{-6} T$

According to the Faraday's law the emf induced in a rod passing transversely through a magnetic field is given as:

$emf= l.v.B$

$emf=13\times 20\times 38\times 10^{-6}$

$emf= 9.88 \times 10^{-3} T$

4 0

2 years ago

Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject

Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

$t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}$

where

$\mu_{sun}$ is gravitational parameter of sun = 1.32712 x 10^20 m^3 s^2. $t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}$

t = 12,105.96 sec

6 0

2 years ago