100 POINTS!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Viktor [21]3 years ago

4 0

The change, from the predicted data to the actual data, in the average number of downloads of the application for Company A from the day the application was launched to 4 days after the application was launched would decrease by approximately 244 downloads per day.

The change, from the predicted data to the actual data, in the average number of downloads of the application for Company B from the day the application was launched to 4 days after the application was launched would increase by approximately 174 downloads per day.

Based on this information, Company B made a more accurate prediction of the average number of downloads of the application per day.

Step2247 [10]3 years ago

3 0

$1. Decrease \\ 2. 244 \\ 3. Increase \\ 4. 175 \\ 5. Company B$

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Sarah has to pay a one-time $300 deposit for her apartment. Each month she pays $700 for rent. How much would Sarah pay for “n”

Alex73 [517]

Answer:

700n + 300

Step-by-step explanation:

We know that no matter what happens, Sarah has to pay a One-Time $300 for her deposit.

Now, we know that for every month she stays in the apartment, it will cost her $700.

So, we can come up with a formula to find out how much she would pay:

700n + 300

Hope this helps!

4 0

3 years ago

(1) a) 5270 cl= ? dal

Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

$a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl$ .

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

$10^3$

Bear in mind these useful relations:

$1litre =\frac{1}{10^3}m^{3}$

$1 cm^{3} =1 ml$

$a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}$