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Travka [436]
2 years ago
5

Compare the shape of a chemical signalling molecule and a receptor.

Chemistry
1 answer:
Andru [333]2 years ago
6 0

Cell signalling is a process by which cells communicate with each other and transfer messages.

<h3>What is a receptor?</h3>

A molecule inside or on the surface of a cell binds to a specific substance and causes a specific effect in the cell.

Cell signalling is a process by which cells communicate with each other and transfer messages. When a signal molecule binds to a receptor protein, changes occur in the receptor proteins. Two changes are listed below:

1. The receptor protein undergoes conformational changes and acts as an enzyme.

2. The receptor protein that makes a second messenger molecule that leads the reaction further to other cells or molecules.

Learn more about the receptor here:

brainly.com/question/6438216

#SPJ1

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3 years ago
You know that an unlabeled bottle contains an aqueous solution of one of the following: AgNO3, KCl, or (NH4)2SO4. A friend sugge
Afina-wow [57]

Answer:

These tests determine the solubility of the compounds formed upon adding the test solution

Explanation:

Addition of Ba(NO₃)₂ will cause a precipitate ((Ba)₂SO₄) to form in the solution of (NH₄)₂SO₄. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is ammonium sulfate can be determined.

Addition of NaCl solution will cause a precipitate (AgCl) to form in the solution of AgNO₃. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is silver nitrate can be determined.

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6 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 15.6 g of carbon were burned in the presence of
NeX [460]

Answer: 5.72 g mass of carbon dioxide was produced

Explanation:

C+O_2\rightarrow CO_2

Moles of C =\frac{\text{mass of carbon}}{\text{molar mass of carbon}}=\frac{15.6 g}{12 g/mol}=1.3 moles

Mass of O_2 reacted = 59.1 g - 17.5 g = 41.6 g

Moles of O_2\text{ reacted}=\frac{\text{mass of}O_2}{\text{molar mass of}O_2}=\frac{41.6 g}{32 g/mol}=1.3 moles

According to reaction 1 mole O_2 produces 1 mole of CO_2 then 1.3 mole of O_2 will produce \frac{1}{1}\times 1.3 moles of CO_2

Mass of CO_2:

=Moles of CO_2 × molar mass ofCO_2 = 1.3 ×44 g/mol =

=57.2 grams

5.72 g mass of carbon dioxide was produced

7 0
3 years ago
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